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3k^2l^-8/6k^7l^-2

|dw:1442358587704:dw|
this?

I think it's this:\[\large\rm \frac{3k^{2}\ell^{-8}}{6k^{7}\ell^{-2}}\]

correct

now how do i do this

yes i does sound right im checking right now

Woooops!
Subtraction Rule of Exponents:\[\large\rm \color{royalblue}{\frac{x^a}{x^b}=x^{a-b}}\]

\[\large\rm \frac{\ell^{-8}}{\ell^{-2}}=\ell^{-8-(-2)}\]

wow thank you so much that is absolutly right

k5 sounds right though :)
2-7 = -5 leaving it in the denominator.

so it is 1/2k^5l^6

From the looks of it it's just l^4 over k5..

\[\large\rm =\frac{1}{2k^5\ell^{6}}\]Ya this sounds right :)

Oh wait. Wait goodness lol I just noticed that mistake thank you for pointing it out.