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anonymous
 one year ago
This question has something to do with quotient rule and simplify. Write your answer in positive exponents.
anonymous
 one year ago
This question has something to do with quotient rule and simplify. Write your answer in positive exponents.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442358587704:dw this?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1I think it's this:\[\large\rm \frac{3k^{2}\ell^{8}}{6k^{7}\ell^{2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now how do i do this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please explain all steps because i will be offline. thank you so much for having the time to help me solve this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay.. I know you can simplify that because of the 3/6 and the 8/2. They both can be simplified. I think you can also simplify the k2 and k7... but let's see. Three and six is easy, you cancel out the 3 and divide 6 by 3, you end up with 1 and 2 right? Move on to the next part. k2 and k7, I believe you can cancel out the k2 and take k2 off of k7 and that leaves you with just k5 in the denominator.. 8 and  2.. they can divide. Cancel out the 2 with 2 and divide 8 by 2. That leaves you with l^4 in the numerator. Does this sound about right..?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i does sound right im checking right now

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Woooops! Subtraction Rule of Exponents:\[\large\rm \color{royalblue}{\frac{x^a}{x^b}=x^{ab}}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \frac{\ell^{8}}{\ell^{2}}=\ell^{8(2)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wow thank you so much that is absolutly right

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1k5 sounds right though :) 27 = 5 leaving it in the denominator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From the looks of it it's just l^4 over k5..

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm =\frac{1}{2k^5\ell^{6}}\]Ya this sounds right :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Rheaaaa >.< I'm confused why you applied `subtraction` to the 2 and 7, but `division` to the 8 and 2 ... hmm weird.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait. Wait goodness lol I just noticed that mistake thank you for pointing it out.
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