anonymous
  • anonymous
Using the two functions listed below, insert numbers in place of letters A,b,c and d so that f(x) and g(x) are inverse
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
what are the two functions...?
anonymous
  • anonymous
stull need help?
anonymous
  • anonymous
Here is the full question Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. f(x)= x+a b g(x)=cx−d Part 2. Show your work to prove that the inverse of f(x) is g(x). Part 3. Show your work to evaluate g(f(x)). Part 4. Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.

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anonymous
  • anonymous
anonymous
  • anonymous
jdoe0001
  • jdoe0001
hmmm have you covered inverse functions yet?
anonymous
  • anonymous
jdoe0001
  • jdoe0001
hmmm need to dash in a bit but hmm what I'd do is, pick two random values for "a" and "b" say 2 and 3 so f(x) = x+ab f(x) = x+(2 * 3) f(x) = x +6
jdoe0001
  • jdoe0001
so, if we use 2 and 3 for "a" and "b" we end up with a function in "x" terms so to find f(x), or "y" we can simply use some "x" value, say 4 f(x) = x +6 x=4 f(x) = 4+6 f(4) = 10
anonymous
  • anonymous
Wait
anonymous
  • anonymous
It's f(x)=x+a/b
jdoe0001
  • jdoe0001
so... all that is thus far f(x) only BUT recall that the domain of one function, is the range of the inverse function that is if we use x= 4, as INPUT, and our OUTPUT is 10 then the inverse would have to take in, 10 and output 4
anonymous
  • anonymous
So y=x+2/3?
jdoe0001
  • jdoe0001
yes... using a/b then get a random value for "x", to get some "y"
anonymous
  • anonymous
Okay so would that be the inverse function for fx?
jdoe0001
  • jdoe0001
so you get some OUTPUT from some INPUT and reverse that on g(x) IF g(x) is to be the inverse function, the OUTPUT of f(x), will serve as the INPUT for g(x)
jdoe0001
  • jdoe0001
and if you use those INPUT and OUTPUT values from f(x) into g(x) you can then solve for either "c" or "d" and use a random "d", to get a "c", or the other way around and g(x) will end up being the inverse because of the INPUT and OUTPUT swap
jdoe0001
  • jdoe0001
anyhow... dashing :)
anonymous
  • anonymous
Okay.... So how would I get the equations

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