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get t in terms of x from this one: x=(1/3)t-1

can you explain some more?

is this correct so far? \[t=((1/3)-1)/x\]

y=3x+3, yes it's a function

oh so just t= \[t=\frac{ 1 }{3 }x-1\]

@whovianchick no, it is not a function
but vinny has some work to do before we get there

sorry his wording confused me its t=3x-3 correct?

not quite

sign on the 3??

positve

and when you have done that we are told that \(y^2 = t^2\)
so stuff your new equation into that

ugh sorry im working on little sleep and silly mistakes are getting me'

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thanks whovian:-)

keep going vinny, we are nearly done!

y=3x=3

You're welcome. You had him working with the wrong equation, and I'm nitpicky like that

ah they are squared gh

yes so just square them, DO NOT multiply/expand out the x side,...!

"You had him working with the wrong equation,"
when?

if y^2 = t^2, then y=t Replace y for t in the equation: y=3x+3, which is a function

yeah thats what i did

thanks guys

no vinny
it is NOT a function

No prob. Sorry @IrishBoy123 earlier he said something like 1/3x-1 = t and I thought it was you

you will see why if we finish this properly
but if you are really tired, go to bed

@IrishBoy123 UMMMMMMMMMMMM y=3x+3 IS a function

it is a function, thatis ture, but that is not what we have here

"thatis ture"
that is true

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That's the answer, I'm confused what you're saying

@vinny0515
are you done for the day?

this is what we have here
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No it's not, and both are functions

so the answer for the quesrion is y=3x+3

no it is not

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y=3x+3 is the answer

how do i answer it then

The way I told you to. y=3x+3, and yes it's a function

irsih boy is right

and that's us done
thank you both:p

so i write the answer as y is not a function

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