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anonymous
 one year ago
find the direct relationship between x and y and determine whether the parametric equations determine y as a function of x
x=(1/3)t1 y^2=t^2
anonymous
 one year ago
find the direct relationship between x and y and determine whether the parametric equations determine y as a function of x x=(1/3)t1 y^2=t^2

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2get t in terms of x from this one: x=(1/3)t1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you explain some more?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2you have x=(1/3)t1, ie an equation giving x in terms of t work it so that you have t in terms of x, ie t = .... use normal algebra

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is this correct so far? \[t=((1/3)1)/x\]

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1y=3x+3, yes it's a function

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2isn't it \[x=\frac{1}{3}t1\]??? all you have to do is move the t across to the RHS and the x across to the RHS, applying usual rules of maipulation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so just t= \[t=\frac{ 1 }{3 }x1\]

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1Well, you have to find out if y is a function of x. first of all, if x=1/3t1, then 3x=t3, and t=3x+3. Then if y^2=t^2, y=t, so y=3x+3. Which is a function. I don't know where you got t=1/3x1. That's not right

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2no, i said "applying usual rules of manipulation". you can't just lift them out(!!) and switch them around an example if \(x = \frac{2}{3} t + 4\) then \(x4 = \frac{2}{3} t\) \(\frac{2}{3}t = x4\) \(t = \frac{3}{2} x  6\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2@whovianchick no, it is not a function but vinny has some work to do before we get there

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1Except that your math is wrong and you're forgetting y. Recheck your math. You can't just switch t and x, you have to solve for t. It's called 7th grade math. I'm in 11th grade math.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry his wording confused me its t=3x3 correct?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2and when you have done that we are told that \(y^2 = t^2\) so stuff your new equation into that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ugh sorry im working on little sleep and silly mistakes are getting me'

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442362440473:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2keep going vinny, we are nearly done!

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1You're welcome. You had him working with the wrong equation, and I'm nitpicky like that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ah they are squared gh

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2yes so just square them, DO NOT multiply/expand out the x side,...!

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2"You had him working with the wrong equation," when?

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1if y^2 = t^2, then y=t Replace y for t in the equation: y=3x+3, which is a function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah thats what i did

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2no vinny it is NOT a function

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1No prob. Sorry @IrishBoy123 earlier he said something like 1/3x1 = t and I thought it was you

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2you will see why if we finish this properly but if you are really tired, go to bed

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1@IrishBoy123 UMMMMMMMMMMMM y=3x+3 IS a function

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2it is a function, thatis ture, but that is not what we have here

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2"thatis ture" that is true

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442362767682:dw

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1That's the answer, I'm confused what you're saying

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2@vinny0515 are you done for the day?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2this is what we have here dw:1442362770822:dw

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1No it's not, and both are functions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer for the quesrion is y=3x+3

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442362943289:dw

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1What is the answer, then? We've replaced y for t, and we're done. What the heck are you talking about?

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1y=3x+3 is the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i answer it then

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1The way I told you to. y=3x+3, and yes it's a function

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2\(y^2=(3x+3)^2\) is what you have if you want to simplify it you can say \(y= \color{red}\pm (3x+3)\) but whatever you do, x maps to 2 y values it is not a function

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1@IrishBoy123 I understand that. But it's saying as one line, is every solution a function. The answer is yes. Both of those equations are functions

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2it is not a function as you can get 2 y's for every x y = 3x+3 is a function y = (3x+3) is a function this is both and is not a function dw:1442363265605:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2and that's us done thank you both:p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i write the answer as y is not a function

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.1Y is a function. I think you're forgetting the concept of a function, @IrishBoy123 , it's ok if there are multiple y's for every x. What you don't want is multiply x's for every y. THAT is the definition of a function, and even with your skewed logic, it's STILL a function. Stop confusing @vinny0515. YOU ARE WRONG

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2dw:1442432889018:dw
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