Identify the standard form of the equation by completing the square.
3x^2 − 2y^2 − 12x − 16y + 4 = 0

Identify the standard form of the equation by completing the square.
3x^2 − 2y^2 − 12x − 16y + 4 = 0

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I know how to begin by factoring the 3 and -2 so you're left with:
3(x^2-4x+4) -2(y+8y+16)= -4

And the next step is to make the constants equal so you get: 3(x^2-4) - 2(y+8)= -24

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