anonymous
  • anonymous
A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
?
misty1212
  • misty1212
multiply
kropot72
  • kropot72
Let A be the event 'misses the first shot' and let B be the event 'misses the second shot. P(A) = 0.4 P(B|A) = 0.05 \[\large P(A \cap B)=P(A) \times P(B|A)\]

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anonymous
  • anonymous
.02 ?
kropot72
  • kropot72
Correct.
anonymous
  • anonymous
is hat the answer
kropot72
  • kropot72
Yes, that value is the probability of missing both free-throw shots.

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