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anonymous

  • one year ago

How do I graph x^2=4y^2? Would someone mind making an x and y chart and showing me?

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  1. zzr0ck3r
    • one year ago
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    first graph \(y_1=\sqrt{\dfrac{x^2}{4}}\) and then on the same graph, graph \[y_2=-\sqrt{\dfrac{x^2}{4}}\]

  2. zzr0ck3r
    • one year ago
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    Because what you put is not a function, so we break it up into functions :)

  3. anonymous
    • one year ago
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    x^2-4y^2=0 (x-2y)(x+2y)=0 so you should draw x-2y=0 and x+2y=0 .

  4. anonymous
    • one year ago
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    look at this http://www.wolframalpha.com/input/?i=plot+x^2%3D4y^2

  5. anonymous
    • one year ago
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    Oh...how do you tell when to break up equations into two functions?

  6. ganeshie8
    • one year ago
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    both look good to me.. amirreza's even better...

  7. zzr0ck3r
    • one year ago
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    sorry I read something completely different on my phone ....

  8. ganeshie8
    • one year ago
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    thats zero product property @one2345 if you have an equation like : \(a*b = 0\), then it must be the case that either \(a = 0\) or \(b=0\) (or both of them equal to \(0\))

  9. anonymous
    • one year ago
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    Oh I see, thank you so much.

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