anonymous
  • anonymous
FInd the area of region enclosed by the given curves y=x+5 y^2=x y=2 y=-1 what I did was sliced it to parts. from o to -1 and 0 to 2 did I do it right? top half delta y and bottom delta x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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freckles
  • freckles
hello are you here? I would start off with a drawing first
freckles
  • freckles
\[\int\limits_{-1}^{2} (\text{ \right }-\text{ \left } )dy\]
anonymous
  • anonymous
yes I understand that and I wanted to split it in half at y=0 and take areas separately would that work? @freckles

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freckles
  • freckles
yes but why do that?
freckles
  • freckles
seems much easier just to do one integral \[\int\limits_{-1}^2 (y^2-(y-5)) dy\]
anonymous
  • anonymous
I guess I am just over thinking it. because today my teacher was talking about splitting integrals too for some equations
freckles
  • freckles
well you have a x=y^2 is right of x=y-5 so x=y^2 is greater than x=y-5
freckles
  • freckles
|dw:1442380700153:dw|
freckles
  • freckles
it is clear from the picture between y=-1 and y=2 we have x=y^2 is greater than x=y-5 you only need one integral
freckles
  • freckles
if the functions had crossed passed and therefore you had some kind of switching of which was greater than you may need more than one integral
freckles
  • freckles
for example if you had: |dw:1442380823519:dw| you would need two integrals here
freckles
  • freckles
|dw:1442380886729:dw| \[\int\limits_{-1}^c (g(y)-f(y))dy+\int\limits_c^2 (f(y)-g(y))\]
anonymous
  • anonymous
ahhhhhhhh I see and yeeah that looks like two different areas for the second example lol thank you!!
freckles
  • freckles
oops forgot to write a dy at the end of that one integral
freckles
  • freckles
\[\int\limits\limits_{-1}^c (g(y)-f(y))dy+\int\limits\limits_c^2 (f(y)-g(y)) \color{red}{ dy}\]

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