Assume that the playbook contains 9 pasing plays and 11 running plays. The coach randomly selects 8 plays from the playbook. What is the probability that the coach selects at least 2 passing plays and at least 3 running plays?

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Assume that the playbook contains 9 pasing plays and 11 running plays. The coach randomly selects 8 plays from the playbook. What is the probability that the coach selects at least 2 passing plays and at least 3 running plays?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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total no .of plays=20
yes
now atleast 2 means 2 or more than 2

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Other answers:

now out of 20 he selects 8
so now we can have the combinations
2 passing,6 running 3 passing,5 running 4 passing,4 running 5 passing,3 running
so 9c2*11c6+9c3*11c5+9c4*11c4+9c5*11c3
now calculate and get the answer
@ pulsified did you understand?
so is the answer 117810/125970
yeah

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