anonymous
  • anonymous
Volume of a given mass of a gas is doubled at atmospheric pressure if the temperature of a gas is changed from 75 degrees to: (A)150 degrees (B)423 degrees (C)75 degrees (D)37.5 degrees
Physics
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anonymous
  • anonymous
Volume of a given mass of a gas is doubled at atmospheric pressure if the temperature of a gas is changed from 75 degrees to: (A)150 degrees (B)423 degrees (C)75 degrees (D)37.5 degrees
Physics
chestercat
  • chestercat
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anonymous
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anonymous
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anonymous
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anonymous
  • anonymous
arindameducationusc
  • arindameducationusc
USE PV=NRT
anonymous
  • anonymous
But i think Charles law is more applicable in it..is'nt it??? @arindameducationusc
arindameducationusc
  • arindameducationusc
YES, P IS CONSTANT
arindameducationusc
  • arindameducationusc
V is proportional to T. if V is doubled, T is doubled
anonymous
  • anonymous
Then acc to you 150 should be the answer but my teacher told me 423 and i dont know how??
arindameducationusc
  • arindameducationusc
hmmm.....
arindameducationusc
  • arindameducationusc
any units given? like kelvin, Fahrenheit, Celsius?
anonymous
  • anonymous
No....unit is not given so we have to give the answer on the same standard as in the question
arindameducationusc
  • arindameducationusc
hmmm. confusing....
arindameducationusc
  • arindameducationusc
@Michele_Laino @Robert136 @irishboy123 can help you,, don't worry!
arindameducationusc
  • arindameducationusc
Ya Even @Astrophysics can give a try.
anonymous
  • anonymous
Sure
IrishBoy123
  • IrishBoy123
the answer is 243 |dw:1442394056979:dw|
anonymous
  • anonymous
Sorry buddy but not understanding why you are adding 273 as we havent been given any unit.???
IrishBoy123
  • IrishBoy123
kelvin https://uk.answers.yahoo.com/question/index?qid=20110502085234AAwq8od
IrishBoy123
  • IrishBoy123
Kelvin is an absolute scale
IrishBoy123
  • IrishBoy123
got it to work yet?
anonymous
  • anonymous
Bro i know all that..but i am just saying that how you knew that 75 degrees in the question is in celsius scale not in kelvin...it can possibly be given in kelvin becoz we havent mentioned any unit in the answer also....... just ''degrees'' not any unit...so it means that we does'nt have to convert 75...
anonymous
  • anonymous
So by keeping 75 how we can get to the answer..??
IrishBoy123
  • IrishBoy123
to get you to the bottom of this, set T to zero in the ideal gas law see what you get
anonymous
  • anonymous
Bro we have to find T2 and by putting T zero all the equation would be zero....i think the above question is a simple condition of Charles law nothing more thn that and the answer should be 150 according to me but my teacher told me thats not the answer answer is 423 and i was just wandering how the hell this can be the answer and i just supposed if there is a trick behind it so just want you to find that out...please...
IrishBoy123
  • IrishBoy123
really sorry mate, finally gave this the attention it deserves and i totally dig what you say here we have: |dw:1442512924916:dw| so #1 \[\frac{1 \times 1}{75K} = \frac{1 \times 2}{X}\] \[X = 2(75) = 150K \] or #2 \[\frac{1 \times 1}{75^oC+273} = \frac{1 \times 2}{X+273}\] \[X+273 = 2(75+273)\] \[X = 423K = 150^oC\] good spot!
anonymous
  • anonymous
Thanks a lot mate...really you are a genius

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