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anonymous

  • one year ago

I need some help with Algebra please! What is the simplified form of each expression? 1. –(10)–1 (1 point) -1/10 -1/1 10 1/10 10 2. 1/c -5 (1 point) c5 5c –c5 – 5/ c 3. What is the value of y-5/x -3 for x = 2 and y = –4? (1 point) 10/3 128 –1/128 –128

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  1. anonymous
    • one year ago
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    I'll medal whoever can help me out i need to turn this in asap and i am absolutely terrible at math but cant let my grade get any lower, anyone that goes to indiana connections help me out please!

  2. anonymous
    • one year ago
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    I know number one is 10. I don't understand the others though.

  3. zepdrix
    • one year ago
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    \[\large\rm -(10)^{-1}\]Is this the first one? :o

  4. zepdrix
    • one year ago
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    Recall that for negative exponents we have this going on\[\large\rm x^{-a}=\frac{1}{x^a}\]And,\[\large\rm \frac{1}{x^{-b}}=x^b\]

  5. anonymous
    • one year ago
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    if it is then 10 won't be the answer it would be -1/10

  6. anonymous
    • one year ago
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    how are you doing that? i couldn't put the questions in correctly thats why there kind of hard to figure out what im asking

  7. anonymous
    • one year ago
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    but yes that is the first one

  8. zepdrix
    • one year ago
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    The equation tool. It takes a little getting used to though :)

  9. anonymous
    • one year ago
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    \[\frac{ 1 }{ c } ^{-5}\] well then this would be question #2 but the exponet on the bottom not the top lol i attempted to use the equation tool

  10. zepdrix
    • one year ago
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    So use the second rule I posted :)

  11. zepdrix
    • one year ago
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    Apply the exponent rule to your 10, flip it in order to change the exponent to positive.\[\large\rm -(10)^{-1}=-\frac{1}{(10)^{+1}}=-\frac{1}{10}\]You were fine with the first one?

  12. anonymous
    • one year ago
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    Oh okay thank you, would number 2 be -c5?

  13. zepdrix
    • one year ago
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    To get rid of the negative on the exponent, flip the c up to the numerator,\[\large\rm \frac{1}{c^{-5}}=\frac{c^{+5}}{1}=c^5\]Be careful with this though, I'm NOT exchanging the c and 1. I'm only moving the c. Example, if this had been your problem:\[\large\rm \frac{2}{c^{-5}}\]It would become\[\large\rm \frac{2c^{+5}}{1}=2c^5\]You're just flipping the c up to the numerator, and the exponent changes to positive. All that's left in the bottom is a 1 pretty much.

  14. anonymous
    • one year ago
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    So it would be \[c^{5}\] not \[-c^{5}\]

  15. zepdrix
    • one year ago
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    correct :)

  16. anonymous
    • one year ago
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    Thank you so much! Do you think you can help me with number 3 as well?

  17. zepdrix
    • one year ago
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    |dw:1442382222840:dw|Apply your exponent rule to each of these BEFORE you plug the values in.

  18. zepdrix
    • one year ago
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    The x will come up top, the 3 will become positive, the y will go down below, the 5 will become positive, ya?

  19. zepdrix
    • one year ago
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    |dw:1442382287125:dw|

  20. zepdrix
    • one year ago
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    I would recommend that you put brackets around your numbers when you plug them in, just to remind yourself that the exponent is being applied to the `negative` sign as well.

  21. anonymous
    • one year ago
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    Would it end up being 128?

  22. zepdrix
    • one year ago
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    |dw:1442382496242:dw|Hmm the bottom number is going to be a lot larger than the top, not sure how you ended up with a big number like that. Should be something really small.

  23. anonymous
    • one year ago
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    Im not good at this at all. . sorry :/ \[\frac{ 10 }{ 3 }\] then?

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