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marcelie
 one year ago
help please !!!!
Find the dimensions of the rectangular corral
producing the greatest enclosed area given 200 feet of
fencing.
marcelie
 one year ago
help please !!!! Find the dimensions of the rectangular corral producing the greatest enclosed area given 200 feet of fencing.

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imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1ok so its likedw:1442384074892:dw ur given that x+y=200 y=200x and the area should be maximum area=x*y area=x*(200x) area=200xx^2 u can get the value of x for which the area will be max by differentiating the area equation which we got with respect to x and equating it to 0 so u get \[\frac{ d}{ dx }(200xx^2) =0\] after differentiating u get 2002x=0 200=2x x=100 and we know that y=200x so y=200100 y=100 so the dimensions are x=100 and y=100 so basically if u are maximizing the area then the figure has to become a square even tho we are given that its a rectangle :)

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0how did u get 200xx^2 =0

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1we are given x+y=200 right so after subtracting x from both sides u get y=200x equation 1 nd we knw that the area is= x*y area=x*y put the value of y from equation 1 u get area=x*(200x) open the bracket u get area=200xx^2 :)

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0okay so then how did u get 2002x =0 ?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1yes u get that after differentiating nd thats the way u do it :)

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0how do u do that ? by subtracting ?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1no the differentiation of x^n with respect to x can be given as \[\frac{ d }{ dx }x^n =nx^\left( n1 \right)\] and if u have something like this  ax^n + b where a and b are constants then the differentiation of this thing with respect to x will be \[\frac{ d }{ dx }(ax^n +b) =\frac{ d }{ dx }ax^n + \frac{ d }{ dx }b\]\[=anx^\left( n1 \right)+0\] basically differentiation of m with respect to n indicates the rate of change of m with respect to n nd here we had a constant b nd we knw that constants are constants so differentiating it with respect to x gave us a 0 but ax^n is not a constant tho it has a but it has also got x^n which keeps changing so we get anx^(n1) on differentiating it ) nd we used this to get 2002x from 200xx^2 :)

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0how would i solve this one ? Find the dimensions of the rectangular corral producing the greatest enclosed area split into 3 pens of the same size given 500 feet of fencing.
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