I want do an AES CBC decryption in Python without padding but I keep getting an error.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I want do an AES CBC decryption in Python without padding but I keep getting an error.

Computer Science
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

from Crypto.Cipher import AES BS = 16 pad = lambda s: s + (BS - len(s) % BS) * chr(BS - len(s) % BS) unpad = lambda s : s[0:-ord(s[-1])] class AESCipher: def __init__( self, key ): self.key = key def encrypt( self, raw ): raw = pad(raw) iv = raw[:16] raw=raw[16:] #iv = Random.new().read( AES.block_size ) cipher = AES.new( self.key, AES.MODE_CBC, iv ) return ( iv + cipher.encrypt( raw ) ).encode("hex") def decrypt( self, enc ): iv = enc[:16] enc= enc[16:] cipher = AES.new(self.key, AES.MODE_CBC, iv ) return unpad(cipher.decrypt( enc)) mode = AES.MODE_CBC key = "blahahahblah ciphertext = blahblahblah key=key[:32] decryptor = AESCipher(key) decryptor.__init__(key) plaintext = decryptor.decrypt(ciphertext) print plaintext
Would I have to decode tbe hex value before decryption?
126 Bit

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

.....
above and beyond my question to unforeseen extents thanks so much mate phuarkin hell
thanks so much
YOU'RE WELCOME DUDE.

Not the answer you are looking for?

Search for more explanations.

Ask your own question