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anonymous
 one year ago
A train leaves the station at 9:00 pm traveling at 36 miles per hour. A second train leaves the station at 10:00pm traveling at 42 miles per hour. At what time will both trains have traveled the same distance?
A.) 4:00 am
B.) 5:00 am
C:) 6:00 am
D:) 7:00
anonymous
 one year ago
A train leaves the station at 9:00 pm traveling at 36 miles per hour. A second train leaves the station at 10:00pm traveling at 42 miles per hour. At what time will both trains have traveled the same distance? A.) 4:00 am B.) 5:00 am C:) 6:00 am D:) 7:00

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Baby_Bear69
 one year ago
Best ResponseYou've already chosen the best response.0I could figure it up and give you the answer, but I do it the difficult way.. Idk how to explain

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I really need the answer I've been stuck for awhile. :/ please help!

Baby_Bear69
 one year ago
Best ResponseYou've already chosen the best response.0Basically im just making a chart. and as you add an hour, add 36 or 42 cause thats how many miles they go per hour

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay thanks :/ I tried that but I think I messed up

Baby_Bear69
 one year ago
Best ResponseYou've already chosen the best response.0can i get a medal please, just hit Best Response

radar
 one year ago
Best ResponseYou've already chosen the best response.1Just in case you are interested in a method to solve this: Distance = Rate (mph) times time (hours) or D=RT This is the relationship you use. For this problem, the distance traveled by first train will equal the distance traveled by second train.

radar
 one year ago
Best ResponseYou've already chosen the best response.1D (distance) of first train = speed of first train times the time that the train traveled D of 2nd train = speed of 2nd train times the time traveled by 2nd train. The unknown here is the times. We now resort to algebra.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0picking up from where @radar left off dw:1442411649060:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.036t = 42(t  1) 36t = 42t  42 6t = 42 t = 7 hours the trains have traveled the same distance 7 hours after the first train leaves the station. That's 4:00 am

radar
 one year ago
Best ResponseYou've already chosen the best response.1Let X = the amount of time traveled by first train. Since 2nd train left an hour later .....then..... X1 = the amount of time traveled by 2nd train. Since the distance traveled at the point where they were at the same place is the same. 36X = 42(X1) Now all that is required is to solve for x. Add the value obtained for x to the time that first train left and you will have the time where both trains traveled the same distance. PS For some reason there was a connection failure.

radar
 one year ago
Best ResponseYou've already chosen the best response.1Let X = the amount of time traveled by first train. Since 2nd train left an hour later .....then..... X1 = the amount of time traveled by 2nd train. Since the distance traveled at the point where they were at the same place is the same. 36X = 42(X1) Now all that is required is to solve for x. Add the value obtained for x to the time that first train left and you will have the time where both trains traveled the same distance. PS For some reason there was a connection failure.

radar
 one year ago
Best ResponseYou've already chosen the best response.1However, I see that @peachpi has provided an excellent solution.
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