anonymous
  • anonymous
WILL FAN AND MEDAL PLEASE HELP The wavelength of red light is given as 6.5 × 10È¥ m. If another wave of an unknown type has a frequency of 5.3 × 10¹¢ Hz. What is the relation between the wavelength of the unknown wave and red light? (note: c = 2.998 × 10§ m/s) The wavelength of the unknown wave is less than the wavelength of the red light the wavelength of the wave is greater than the wavelength of the red light the wavelength of the wave is equal to the wavelength red light the wavelength of the wave is not related to the wavelength of the red light
Chemistry
chestercat
  • chestercat
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Rushwr
  • Rushwr
\[c = f \lambda \]
Rushwr
  • Rushwr
c = velocity f= frequency \[\lambda = wavelength \]
anonymous
  • anonymous
I have no clue what to do with that...

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anonymous
  • anonymous
I think it's A but I'm not sure...
Rushwr
  • Rushwr
to compare the wavelengths we have to obtain a value for the wavelength of the unknown wave using the above equation obtain a value. \[\lambda = \frac{ c }{ f } \]
anonymous
  • anonymous
So... C? because that's what's looking right now...
Rushwr
  • Rushwr
no no !! Wait I'll tell you but tell me the value for C !!! It's a little unclear !
Rushwr
  • Rushwr
if u don't mind right the values here again it's a little unclear !! type it here, don't copy paste
anonymous
  • anonymous
2.998*10^8 m/s
anonymous
  • anonymous
sorry open study turns the notations into weird symbols
Rushwr
  • Rushwr
what about the values for others !!! It's not clear ! ^_^
anonymous
  • anonymous
6.5*10^-7 is the first one and 5.3*10^15
Rushwr
  • Rushwr
aaah okai. Now we know the wavelength of the red light. We are given with the frequency of the unknown wave. Looking at the answers we can see that they have compared the wavelengths. We only know the wavelength of the red light, to compare the wavelengths we have to find the wavelength of the unknown wave right? Do u understand up to this point ?
anonymous
  • anonymous
I do.
anonymous
  • anonymous
I just don't know how to find the wave length, I get confused with the numbers
Rushwr
  • Rushwr
Now we have to find the wavelength of the unknown wave. So we are gonna use the above equation: \[c = f \lambda \] \[\lambda = \frac{ c }{ f } = \frac{ 2.998 * 10^{8} }{ 5.3 * 10^{15} }\]
Rushwr
  • Rushwr
\[\lambda = 5.65 * 10^{-8}\]
Rushwr
  • Rushwr
As we can see that the unknown wave has a shorter wavelength than the red light !
anonymous
  • anonymous
Thank you!

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