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anonymous
 one year ago
WILL FAN AND MEDAL PLEASE HELP
The wavelength of red light is given as 6.5 × 10È¥ m. If another wave of an unknown type has a frequency of 5.3 × 10¹¢ Hz. What is the relation between the wavelength of the unknown wave and red light? (note: c = 2.998 × 10§ m/s)
The wavelength of the unknown wave is less than the wavelength of the red light
the wavelength of the wave is greater than the wavelength of the red light
the wavelength of the wave is equal to the wavelength red light
the wavelength of the wave is not related to the wavelength of the red light
anonymous
 one year ago
WILL FAN AND MEDAL PLEASE HELP The wavelength of red light is given as 6.5 × 10È¥ m. If another wave of an unknown type has a frequency of 5.3 × 10¹¢ Hz. What is the relation between the wavelength of the unknown wave and red light? (note: c = 2.998 × 10§ m/s) The wavelength of the unknown wave is less than the wavelength of the red light the wavelength of the wave is greater than the wavelength of the red light the wavelength of the wave is equal to the wavelength red light the wavelength of the wave is not related to the wavelength of the red light

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Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1c = velocity f= frequency \[\lambda = wavelength \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no clue what to do with that...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think it's A but I'm not sure...

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1to compare the wavelengths we have to obtain a value for the wavelength of the unknown wave using the above equation obtain a value. \[\lambda = \frac{ c }{ f } \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So... C? because that's what's looking right now...

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1no no !! Wait I'll tell you but tell me the value for C !!! It's a little unclear !

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1if u don't mind right the values here again it's a little unclear !! type it here, don't copy paste

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry open study turns the notations into weird symbols

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1what about the values for others !!! It's not clear ! ^_^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06.5*10^7 is the first one and 5.3*10^15

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1aaah okai. Now we know the wavelength of the red light. We are given with the frequency of the unknown wave. Looking at the answers we can see that they have compared the wavelengths. We only know the wavelength of the red light, to compare the wavelengths we have to find the wavelength of the unknown wave right? Do u understand up to this point ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just don't know how to find the wave length, I get confused with the numbers

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Now we have to find the wavelength of the unknown wave. So we are gonna use the above equation: \[c = f \lambda \] \[\lambda = \frac{ c }{ f } = \frac{ 2.998 * 10^{8} }{ 5.3 * 10^{15} }\]

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1\[\lambda = 5.65 * 10^{8}\]

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1As we can see that the unknown wave has a shorter wavelength than the red light !
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