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anonymous

  • one year ago

In a game you bet $1 and toss two coins. If two heads come up, you win a profit of 75 cents. If two tails come up, no one wins anything. Otherwise, you lose your dollar. QUESTION: What is the expected value for this game?

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  1. is3535
    • one year ago
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    You couldtoss two coins many, many times and record the experimental results, or you can get the expected value if you assume: 1. the coins are independent (that is, the result of one coin does not influence the value of the other) 2. each coin is “honest.” That is, the probabilities of coming up heads or tails are equal) Note that for each value, heads or tails, of the first coin, the second coin can independently have the value of heads or tails. That means there are 2*2 = 4 possible results (equally likely). Now, of the 4 possible outcomes, here is how we do: H H keep $1 and win profit of 75 cents H T lose $1 T H lose $1 T T no one wins anything So, if you play the game N times, you can expect (in cents): E = (1/4)*175 + (1/4)*(-100) + (1/4)*(-100) + (1/4) (0) E = (1/4)*(-25) = -6.25 For N tries at this game, I expect to lose 6.25*N cents BY I.L

  2. is3535
    • one year ago
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    or - 0.3125

  3. anonymous
    • one year ago
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    Thank you for taking the time to respond in detail! Really appreciate the help! @is3535

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