iwanttogotostanford
  • iwanttogotostanford
NEED HELP ASAP PLEASE: Solve x^2 + 8x − 3 = 0 using the completing-the-square method. x = four plus or minus the square root of three x = negative four plus or minus the square root of three x = four plus or minus the square root of nineteen x = negative four plus or minus the square root of nineteen
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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iwanttogotostanford
  • iwanttogotostanford
@pooja195 @Nnesha
Jack1
  • Jack1
complete the square is: turn this \(\large ax^2 + bx + c = 0\) into this \(\large a(x+d)2 + e = 0\) remember: \(\Large d = \frac b{2a} \) \(\Large e = c - \frac{b^2}{4a}\)
iwanttogotostanford
  • iwanttogotostanford
so it would be C right???

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Jack1
  • Jack1
your equation is: \(\large x^2 + 8x + (-3) = 0\) so turn it into this: \(\large a(x+d)2 + e = 0\) by first solving: \(\Large d = \frac b{2a} =???\) \(\Large e = c - \frac{b^2}{4a} = ??? \)
iwanttogotostanford
  • iwanttogotostanford
ok, and i go C
Jack1
  • Jack1
correct, C
iwanttogotostanford
  • iwanttogotostanford
it is really? i did it right?:-D
Jack1
  • Jack1
yep
iwanttogotostanford
  • iwanttogotostanford
tjanks!
Jack1
  • Jack1
np
iwanttogotostanford
  • iwanttogotostanford
could you help with one more? @Jack1
Jack1
  • Jack1
wait... neg 4 negative 4! dammit, sorrt D not C
Jack1
  • Jack1
*sorry ;(
iwanttogotostanford
  • iwanttogotostanford
aww ok:-( thanks again! can i ask you one more
Jack1
  • Jack1
sure
iwanttogotostanford
  • iwanttogotostanford
Using the completing-the-square method, find the vertex of the function f(x) = –2x^2 + 12x + 5 and indicate whether it is a minimum or a maximum and at what point. Maximum at (–3, 5) Minimum at (–3, 5) Maximum at (3, 23) Minimum at (3, 23)
Jack1
  • Jack1
ok, so have u completed the square?
iwanttogotostanford
  • iwanttogotostanford
yes
Jack1
  • Jack1
and ur equation is now...?
iwanttogotostanford
  • iwanttogotostanford
2x^2+35x?
Jack1
  • Jack1
no. what are a, b and c in ur original equation?
iwanttogotostanford
  • iwanttogotostanford
X2 8 -2
Jack1
  • Jack1
no. \(\large ax^2 + bx + c = 0\) \(\large 2x^2 + 12x + 5 = 0\) so a is 2 b is 12 c is 5... right?
Jack1
  • Jack1
u with me?
Jack1
  • Jack1
r u still there?
iwanttogotostanford
  • iwanttogotostanford
yes! sorry what now? @jack1

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