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Babyslapmafro
 one year ago
Could someone please check my work? I'm trying to solve for G in the following equation (click to see).
Babyslapmafro
 one year ago
Could someone please check my work? I'm trying to solve for G in the following equation (click to see).

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some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i can try

Babyslapmafro
 one year ago
Best ResponseYou've already chosen the best response.2\[n(\frac{ 100 }{ M })^{2}= 2^{G1}\]

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0im not sure i depends on what it is ...

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0sorry im not sure... check with someone more experienced than I @Nnesha

Babyslapmafro
 one year ago
Best ResponseYou've already chosen the best response.2My solution: \[G=\frac{ \ln(25(\frac{ 100 }{ M })^{2}) }{ \ln(2) }+1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got this. Is n supposed to be 25? dw:1442418088603:dw

Babyslapmafro
 one year ago
Best ResponseYou've already chosen the best response.2Oh ya I accidentaly substiuted the value for n prematurely

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok. your's looks good then

Babyslapmafro
 one year ago
Best ResponseYou've already chosen the best response.2So we got the same answer, ok. I substituted the values into the equation and my answer differs from the answer in the back of my book.
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