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Babyslapmafro

  • one year ago

Could someone please check my work? I'm trying to solve for G in the following equation (click to see).

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  1. some.random.cool.kid
    • one year ago
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    i can try

  2. Babyslapmafro
    • one year ago
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    \[n(\frac{ 100 }{ M })^{2}= 2^{G-1}\]

  3. some.random.cool.kid
    • one year ago
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    im not sure i depends on what it is ...

  4. some.random.cool.kid
    • one year ago
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    it*

  5. some.random.cool.kid
    • one year ago
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    sorry im not sure... check with someone more experienced than I @Nnesha

  6. Babyslapmafro
    • one year ago
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    My solution: \[G=\frac{ \ln(25(\frac{ 100 }{ M })^{2}) }{ \ln(2) }+1\]

  7. anonymous
    • one year ago
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    I got this. Is n supposed to be 25? |dw:1442418088603:dw|

  8. Babyslapmafro
    • one year ago
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    Oh ya I accidentaly substiuted the value for n prematurely

  9. anonymous
    • one year ago
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    oh ok. your's looks good then

  10. Babyslapmafro
    • one year ago
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    So we got the same answer, ok. I substituted the values into the equation and my answer differs from the answer in the back of my book.

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