Babyslapmafro one year ago Could someone please check my work? I'm trying to solve for G in the following equation (click to see).

1. some.random.cool.kid

i can try

2. Babyslapmafro

$n(\frac{ 100 }{ M })^{2}= 2^{G-1}$

3. some.random.cool.kid

im not sure i depends on what it is ...

4. some.random.cool.kid

it*

5. some.random.cool.kid

sorry im not sure... check with someone more experienced than I @Nnesha

6. Babyslapmafro

My solution: $G=\frac{ \ln(25(\frac{ 100 }{ M })^{2}) }{ \ln(2) }+1$

7. anonymous

I got this. Is n supposed to be 25? |dw:1442418088603:dw|

8. Babyslapmafro

Oh ya I accidentaly substiuted the value for n prematurely

9. anonymous

oh ok. your's looks good then

10. Babyslapmafro

So we got the same answer, ok. I substituted the values into the equation and my answer differs from the answer in the back of my book.