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anonymous
 one year ago
what is the square root of 3.1
anonymous
 one year ago
what is the square root of 3.1

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0You can simply use a calculator, or do a Taylor approximation of some Nth degree. The first degree approximation, otherwise known as linearization, using \(f(x)=\sqrt{x}\) where \(a=4\), you get: \(\large\color{black}{ \displaystyle {\rm L}(3.1)=f(a)+f'(a)\left(xa\right)}\) \(\large\color{black}{ \displaystyle {\rm L}(3.1)=\sqrt{4}+\frac{1}{2 \sqrt{4}} \left(3.14\right)}\) \(\large\color{black}{ \displaystyle {\rm L}(3.1)=2+\frac{1}{4} \left(0.9\right)}\) \(\large\color{black}{ \displaystyle \sqrt{3.1}\approx20.225=1.775}\)
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