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anonymous
 one year ago
pls factor this with solutions 12p^2q  78pq^2270q^3
anonymous
 one year ago
pls factor this with solutions 12p^2q  78pq^2270q^3

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You just posted this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it was supposed to be factored haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, got you. Alright. So we need to factor this..? \[p=\frac{ 78q^2\pm 138 \sqrt{q^4} }{ 24q }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It would then factor down to ... \[p=9q\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no no just the eqation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.012p^2q  78pq^2270q^3 < this one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OHHHH xD I was solving it with particular method then factoring it.. Okay. My bad, alright hold on. I can get you the proper answer :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we're going to factor the following: \[12p^2q  78pq^2270q^3\] First, you want to factor the common terms out of the equation. factor 6q out of \[12p^2q  78pq^2270q^3\] Leaving you with.. \[6q(2p^213pq45q^2)\] Giving you the final answer of.. \[6q(2p+5q)(p9q)\]
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