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anonymous

  • one year ago

pls factor this with solutions 12p^2q - 78pq^2-270q^3

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  1. anonymous
    • one year ago
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    You just posted this?

  2. anonymous
    • one year ago
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    it was supposed to be factored haha

  3. anonymous
    • one year ago
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    Oh, got you. Alright. So we need to factor this..? \[p=\frac{ 78q^2\pm 138 \sqrt{q^4} }{ 24q }\]

  4. anonymous
    • one year ago
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    It would then factor down to ... \[p=9q\]

  5. anonymous
    • one year ago
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    no no just the eqation

  6. anonymous
    • one year ago
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    12p^2q - 78pq^2-270q^3 <-- this one

  7. anonymous
    • one year ago
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    OHHHH xD I was solving it with particular method then factoring it.. Okay. My bad, alright hold on. I can get you the proper answer :P

  8. anonymous
    • one year ago
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    okay okay

  9. anonymous
    • one year ago
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    So we're going to factor the following: \[12p^2q - 78pq^2-270q^3\] First, you want to factor the common terms out of the equation. factor 6q out of \[12p^2q - 78pq^2-270q^3\] Leaving you with.. \[6q(2p^2-13pq-45q^2)\] Giving you the final answer of.. \[6q(2p+5q)(p-9q)\]

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