anonymous
  • anonymous
pls factor this with solutions 12p^2q - 78pq^2-270q^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
You just posted this?
anonymous
  • anonymous
it was supposed to be factored haha
anonymous
  • anonymous
Oh, got you. Alright. So we need to factor this..? \[p=\frac{ 78q^2\pm 138 \sqrt{q^4} }{ 24q }\]

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anonymous
  • anonymous
It would then factor down to ... \[p=9q\]
anonymous
  • anonymous
no no just the eqation
anonymous
  • anonymous
12p^2q - 78pq^2-270q^3 <-- this one
anonymous
  • anonymous
OHHHH xD I was solving it with particular method then factoring it.. Okay. My bad, alright hold on. I can get you the proper answer :P
anonymous
  • anonymous
okay okay
anonymous
  • anonymous
So we're going to factor the following: \[12p^2q - 78pq^2-270q^3\] First, you want to factor the common terms out of the equation. factor 6q out of \[12p^2q - 78pq^2-270q^3\] Leaving you with.. \[6q(2p^2-13pq-45q^2)\] Giving you the final answer of.. \[6q(2p+5q)(p-9q)\]

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