## anonymous one year ago pls factor this with solutions 12p^2q - 78pq^2-270q^3

1. anonymous

You just posted this?

2. anonymous

it was supposed to be factored haha

3. anonymous

Oh, got you. Alright. So we need to factor this..? $p=\frac{ 78q^2\pm 138 \sqrt{q^4} }{ 24q }$

4. anonymous

It would then factor down to ... $p=9q$

5. anonymous

no no just the eqation

6. anonymous

12p^2q - 78pq^2-270q^3 <-- this one

7. anonymous

OHHHH xD I was solving it with particular method then factoring it.. Okay. My bad, alright hold on. I can get you the proper answer :P

8. anonymous

okay okay

9. anonymous

So we're going to factor the following: $12p^2q - 78pq^2-270q^3$ First, you want to factor the common terms out of the equation. factor 6q out of $12p^2q - 78pq^2-270q^3$ Leaving you with.. $6q(2p^2-13pq-45q^2)$ Giving you the final answer of.. $6q(2p+5q)(p-9q)$