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anonymous

  • one year ago

(f)X=2x+4 3 for X

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  1. anonymous
    • one year ago
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    please someone help

  2. anonymous
    • one year ago
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    @skyvibe

  3. SolomonZelman
    • one year ago
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    You meant: \(\large\color{black}{ \displaystyle f(x)=2x+4 }\) is that right?

  4. anonymous
    • one year ago
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    yea sorry

  5. anonymous
    • one year ago
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    can u walk me through it

  6. SolomonZelman
    • one year ago
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    So, you want to find the value of \(f(x)\), when \(x=3\). That means you have to plug in \(3\) instead of \(x\) into the function \(f(x)\).

  7. anonymous
    • one year ago
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    f(3)=2x+4

  8. SolomonZelman
    • one year ago
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    \(\large\color{black}{ \displaystyle f(x)=2x+4 }\) \(\large\color{black}{ \displaystyle f(\color{red}{3})=2\cdot \color{red}{3}+4= {~}\bf ? }\)

  9. anonymous
    • one year ago
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    sorry tyler i don't get this but i'll give ya a medal :)

  10. anonymous
    • one year ago
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    thank you

  11. anonymous
    • one year ago
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    np

  12. anonymous
    • one year ago
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    and its fine don't worry

  13. SolomonZelman
    • one year ago
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    Tyler, did you find f(3) ?

  14. anonymous
    • one year ago
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    10

  15. SolomonZelman
    • one year ago
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    Yes, f(3)=10

  16. anonymous
    • one year ago
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    ok is that it or no right

  17. SolomonZelman
    • one year ago
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    By the way, there was a dude, X-friend of my friend whose name was Tyler. While I was on vacation he got into my house and robbed my family. (Luckly he only took 200$) LOL

  18. SolomonZelman
    • one year ago
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    Yes, that is it.... you are done:)

  19. anonymous
    • one year ago
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    thank you

  20. SolomonZelman
    • one year ago
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    np

  21. anonymous
    • one year ago
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    I'm doing favs and i have a dba if i have a question can i message u for help

  22. anonymous
    • one year ago
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    FLVS

  23. SolomonZelman
    • one year ago
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    Well, usually I don't reply to messages when people question me through messsages. If I see your question, and I am actually online, then I will probably help you out.

  24. SolomonZelman
    • one year ago
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    Good luck!

  25. anonymous
    • one year ago
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    thank you

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