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cpinder

  • one year ago

Estimate the temperature at which 40 kg of ethane stored in a 0.15 m3 vessel exerts a pressure of 20000 kPa.

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  1. cpinder
    • one year ago
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    So far, I've got calculated the volume like this. Vt=0.15m3=150000cm3 V=V/MW=150000cm3/(40kg*30mol/kg) = 112500 cm3/mol And I've calculated Pr like so. Pr=P/Pc= (20000 kPa*.01 bar/kPa) / 48.72 bar = 4.105 I'm lost from here.

  2. aaronq
    • one year ago
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    Why not just use the ideal gas law?

  3. cpinder
    • one year ago
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    @aaronq we can't use the ideal gas law because this is a non ideal gas. It has a compressibility factor of z, which we don't know. I'm looking at the solution manual right now and this is what it says. PV=ZRT=ZRTrTc Tr=alpha/Z where alpha=PVR/Tc alpha=29.548mol/kg (Tried to get this but I couldn't) whence Tr=0.889/Z at Pr=P/Pc (I've calculated Pr already) This equation giving Tr as a function of Z and eq (3.57) in conjunction with tables E3 and E4 are two relations in the same variables which must be satisfied at the given reduced pressure. The intersection of these two relations can be found by one means or another to occur at about: Tr=1.283 and Z=0.693 From there, T=TrTc=391.7K or 118.5C

  4. aaronq
    • one year ago
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    Oh okay, you're into real gases now

  5. aaronq
    • one year ago
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    I can help you with this later, cuz i gotta go. Hopefully someone else capable comes before hand if you need this asap. I'll look back at this question later today

  6. cpinder
    • one year ago
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    @aaronq just realized I put this in chemistry and not in thermodynamics.

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