anonymous
  • anonymous
Solve x^2 + 10x - 11 = 0 by completing the square Ok, so I need help with this, I have the answer and I know how to do it, I just want to check it.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
campbell_st
  • campbell_st
ok... to you need to group a few things \[x^2 + 10x = 11\] to complete the square find half of 10 and then square it... that's the value that makes the perfect square then add it to both sides..
anonymous
  • anonymous
Ok that's a bit different then how I learned it but I think it's pretty much the same thing.. I would do x^2 + 10x + 25=11+25 Then group it to where it's (X+5)^2=36 Then you would put the (x+5)^2 under a radical sign, and the 36 under the radical sign, and you can't forget the plus and minus sign
campbell_st
  • campbell_st
that's correct

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
But I don't know what to do after
campbell_st
  • campbell_st
ok... so when you take the square root there are 2 solutions, the positive and negative so take the square root of both sides \[x + 5 = \pm \sqrt{36} ~~or~~~x + 5 = \pm 6\] now subtract 5 from both sides of the equation and you get \[x = -5 \pm 6\] so you ahve 2 equations x = -5 -6 and x = -5 + 6 does that make sense
anonymous
  • anonymous
Yes, see, I did all that But I had three instead of six. But thank you so much! I'm glad I checked with someone :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.