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## Compassionate one year ago @BloomLocke367

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1. Compassionate

a = 1, b = 6, c = 5 Solve using the Quadratic Formula

2. Compassionate

ANS: -5 or -1 -(2/5) or -(1/2) -(2/5) or -(1/3) 5 or 1

3. BloomLocke367

okay and you already know the quadratic formula. $$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

4. Compassionate

$\frac{ -6 \pm \sqrt{6^2 - 20} }{ 2}$ This would be a simpler form of the formula given the terms. I just eliminated the a = 1 and added the -4(5).

5. BloomLocke367

yep. now square the 6 under the radical

6. BloomLocke367

I'm sure you know what $$6^2$$is right?

7. Compassionate

$\frac{ -6 \pm 3.5 }{ 2 }$

8. Compassionate

The problem being, when I solve, I get 4.75 and -1.25, which if you look at the answers above, these are not it.

9. BloomLocke367

okay, first off, how did you get 3.5?

10. BloomLocke367

$$6^2=36$$ so you would take $$\large\sqrt{36-20}$$. What is 36-20?

11. Compassionate

$\frac{ -6 \pm \sqrt{36 - 20}}{ 2} = \frac{ -6 \pm \sqrt{12} }{ 2 }$ $\sqrt{12} = 3.5$

12. BloomLocke367

36-20 does not equal 12. double check your math there

13. BloomLocke367

@Compassionate

14. Compassionate

$\frac{ -6 \pm 16 }{ 2} = 5 \space or \space -10$

15. Compassionate

ANS: -5 or -1 -(2/5) or -(1/2) -(2/5) or -(1/3) 5 or 1

16. BloomLocke367

you forgot something. $$\large\sqrt{16}=?$$

17. BloomLocke367

because you have $$\LARGE \frac{-6\pm\sqrt{16}}{2}$$

18. Compassionate

right. Even if you take 4 $\frac{ -6 \pm 4 }{ 2 } = -2/2 = -1 \space or -5$

19. Compassionate

there it is. I was a mess.

20. Compassionate

I'm giving the computer back to my girlfriend. Thanks!

21. BloomLocke367

hahaha it's alright :) do you need any other help? I'll be happy to help. Sometimes you just have to slow down a bit and think xp

22. BloomLocke367

you're welcome! :D you know where to find me if needed.

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