anonymous
  • anonymous
Find the value of the discriminant. Describe the number and type of roots. 4x^2 - 6x + 2 =0 I tried it at least, and I got 4 for the discriminant... That's all I know, and I don't even know if it's right. So please, help me.. I suck at math
Mathematics
katieb
  • katieb
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Nnesha
  • Nnesha
\(\huge\color{reD}{\rm b^2-4ac}\) `Discriminant` you can use this to find if the equation is factorable or not if ` b^2-4ac > 0` then there are 2 real zeros if ` b^2-4ac = 0` then there is one real root if ` b^2-4ac < 0` then you will get two complex roots (no -x-intercept)
anonymous
  • anonymous
Ok, so i did do that, and i got four for the discriminant. Does that mean that the root is 2, and that it is a complex root?
Nnesha
  • Nnesha
4 is greater than or less than 0 ?

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anonymous
  • anonymous
Um.. I think...? I'm very unsure about math. It is not my forte. I just got very confused..
Nnesha
  • Nnesha
so 4 is greater than 0 right ? 4 is bigger than 0 ?
anonymous
  • anonymous
yes
Nnesha
  • Nnesha
do b^2-4ac = 4 4>0 now read my first comment
Nnesha
  • Nnesha
if b^2-4ac> 0 then how many roots would you have ?
anonymous
  • anonymous
Two real zeros one, correct?
anonymous
  • anonymous
oh, sorry didnt see the second comment. and uh, im not sure
Nnesha
  • Nnesha
yes right if you get positive number then you get 2 solutions
Nnesha
  • Nnesha
remember if discriminant = 0 then one solution if discriminant is a negative number then no real solution and if discriminant is positive number then 2 solutions
anonymous
  • anonymous
ohh, that makes sense! I never learned anything about roots. so since its positive, it will have 2 solutions, in other words, 2 roots. correct?
Nnesha
  • Nnesha
yes right!
anonymous
  • anonymous
Awesome! Thank you so much for your time and help. I really appreciate it.
Nnesha
  • Nnesha
my pleasure :=) good work!!

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