## anonymous one year ago Find the value of the discriminant. Describe the number and type of roots. 4x^2 - 6x + 2 =0 I tried it at least, and I got 4 for the discriminant... That's all I know, and I don't even know if it's right. So please, help me.. I suck at math

1. Nnesha

$$\huge\color{reD}{\rm b^2-4ac}$$ Discriminant you can use this to find if the equation is factorable or not if  b^2-4ac > 0 then there are 2 real zeros if  b^2-4ac = 0 then there is one real root if  b^2-4ac < 0 then you will get two complex roots (no -x-intercept)

2. anonymous

Ok, so i did do that, and i got four for the discriminant. Does that mean that the root is 2, and that it is a complex root?

3. Nnesha

4 is greater than or less than 0 ?

4. anonymous

Um.. I think...? I'm very unsure about math. It is not my forte. I just got very confused..

5. Nnesha

so 4 is greater than 0 right ? 4 is bigger than 0 ?

6. anonymous

yes

7. Nnesha

do b^2-4ac = 4 4>0 now read my first comment

8. Nnesha

if b^2-4ac> 0 then how many roots would you have ?

9. anonymous

Two real zeros one, correct?

10. anonymous

oh, sorry didnt see the second comment. and uh, im not sure

11. Nnesha

yes right if you get positive number then you get 2 solutions

12. Nnesha

remember if discriminant = 0 then one solution if discriminant is a negative number then no real solution and if discriminant is positive number then 2 solutions

13. anonymous

ohh, that makes sense! I never learned anything about roots. so since its positive, it will have 2 solutions, in other words, 2 roots. correct?

14. Nnesha

yes right!

15. anonymous

Awesome! Thank you so much for your time and help. I really appreciate it.

16. Nnesha

my pleasure :=) good work!!