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anonymous

  • one year ago

5-(4/k)-(1/k^2)=0 show work

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  1. SolomonZelman
    • one year ago
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    \(\large\color{black}{ \displaystyle 5-\frac{4}{k} -\frac{1}{k^2}=0 }\)

  2. SolomonZelman
    • one year ago
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    You can multiply each times \(k^2\), and you will get a quadratic equation.

  3. SolomonZelman
    • one year ago
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    I meant each *term* times \(k^2\)

  4. anonymous
    • one year ago
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    can you show me

  5. SolomonZelman
    • one year ago
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    \(\large\color{black}{ \displaystyle 5\color{red}{\times k^2}-\frac{4}{k} \color{red}{\times k^2}-\frac{1}{k^2}\color{red}{\times k^2}=0 }\)

  6. SolomonZelman
    • one year ago
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    then simplify...

  7. SolomonZelman
    • one year ago
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    \(\large\color{black}{ \displaystyle 5 k^2-4k-1=0 }\)

  8. anonymous
    • one year ago
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    is that the answer you get?

  9. SolomonZelman
    • one year ago
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    That is not the answer, all I have done is rearranged/worked your equation into a quadratic equation.

  10. SolomonZelman
    • one year ago
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    Now you have to solve it. You can apply the *quadratic formula*

  11. anonymous
    • one year ago
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    oh ok

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