anonymous one year ago 5-(4/k)-(1/k^2)=0 show work

1. SolomonZelman

$$\large\color{black}{ \displaystyle 5-\frac{4}{k} -\frac{1}{k^2}=0 }$$

2. SolomonZelman

You can multiply each times $$k^2$$, and you will get a quadratic equation.

3. SolomonZelman

I meant each *term* times $$k^2$$

4. anonymous

can you show me

5. SolomonZelman

$$\large\color{black}{ \displaystyle 5\color{red}{\times k^2}-\frac{4}{k} \color{red}{\times k^2}-\frac{1}{k^2}\color{red}{\times k^2}=0 }$$

6. SolomonZelman

then simplify...

7. SolomonZelman

$$\large\color{black}{ \displaystyle 5 k^2-4k-1=0 }$$

8. anonymous

is that the answer you get?

9. SolomonZelman

That is not the answer, all I have done is rearranged/worked your equation into a quadratic equation.

10. SolomonZelman

Now you have to solve it. You can apply the *quadratic formula*

11. anonymous

oh ok