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anonymous one year ago i give metals and i will be your fan. What is the value of the expression 7^3?

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1. anonymous

@SolomonZelman @Nnesha

2. Nnesha

the exponents tells how many times you should multiply the base 2^4 = 2 times 2 times 2 times 2

3. adilalvi

343

4. anonymous

the 4 is a negative

5. anonymous

so -343

6. Nnesha

ohh then you should apply the exponent rule $\huge\rm 7^{-3}$ like this ?

7. anonymous

ya

8. Nnesha

$\huge\rm x^{-m}=\frac{ 1 }{ x^m }$ flip the fraction when u flip it , the sign of the exponent would change

9. adilalvi

yaah if its negitive then it will be -343

10. anonymous

so $1/343$

11. Nnesha

yes right

12. anonymous

can you help me with more

13. Nnesha

i'll try :=)

14. anonymous

What is the value of the expression ? 1/5^-5

15. anonymous

|dw:1442438136962:dw|

16. Nnesha

okay apply the same rule!

17. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha $\huge\rm x^{-m}=\frac{ 1 }{ x^m }$ flip the fraction when u flip it , the sign of the exponent would change $$\color{blue}{\text{End of Quote}}$$ exponent is negative so ^^^^^^

18. anonymous

3125 is the anwser

19. Nnesha

well don't use the calculator.

20. anonymous

1/3125

21. Nnesha

no flip the fraction

22. anonymous

how can you show me

23. Nnesha

okay if i have $\huge\rm 2^{-2} =\frac{ 1 }{ 2^2 }$ i would flip the fraction and change the sign of exponent

24. anonymous

so it would just be 3125

25. Nnesha

yes right i guess you don't have to find 5^5

26. Nnesha

are there answer choices ?

27. anonymous

yes

28. Nnesha

okay then that's right

29. anonymous

A. 1/3125 B.1/25 C.25 D.3125

30. Nnesha

ookay. then ur answer is correct :=)

31. anonymous

so D

32. Nnesha

yes

33. anonymous

What is the value of the expression

34. Nnesha

rewrite 4 in terms of base 2

35. anonymous

here are the options

36. anonymous

so 4/3

37. Nnesha

no.. here is an example rewrite 9 in terms of base 3 = 3^2

38. Nnesha

we need to get the same base at the numerator and at the denominator.

39. anonymous

OK

40. anonymous

2^2=4

41. Nnesha

yes right $\huge\rm \frac{ 2 }{ (2^2)^{-3} }$ to solve that you need to know two exponent rules first one is $\huge\rm (x^m)^n=x^{m · n}$ and then when we divide same bases we should subtract their exponents $\large\rm \frac{ x^b }{x^c }=x^{b-c}$

42. anonymous

would it be 1/32

43. Nnesha

nope.

44. Nnesha

how did you get that ?

45. anonymous

256

46. Nnesha

hmm how ?..

47. anonymous

is it right

48. Nnesha

well plz show ur work so i can find where udid a mistake.

49. anonymous

plz tell me if it is right or not first

50. Nnesha

well that's a guess

51. anonymous

so it is not right is it

52. anonymous

128

53. Nnesha

$\huge\rm (2^2)^{-3}$ we should solve it apply the exponent rule $\huge\rm (x^m )^n =x^{m \times n}$ multiply the exponents

54. anonymous

plz just tell me the answer i only have 2 more minutes to finish it

55. Nnesha

we can solve this in two minutes i can't give u the answer plz try to understand

56. anonymous

-64

57. Nnesha

no just multiply the exponents

58. anonymous

5

59. Nnesha

$\huge\rm (2^2)^{-3} =2^{2 \times -3}$ base would stay the same

60. Nnesha

no it's not 5

61. Nnesha

2 times -3 = ?

62. anonymous

-6

63. Nnesha

$\huge\rm \frac{ 2^1 }{ 2^{-6} }$ now subtract the exponent

64. anonymous

-5

65. Nnesha

here is an exxample $\huge\rm \frac{ 3^2 }{ 3^{-3} }=3^{2-(-3)} =3^{2+3}=3^5$

66. Nnesha

no you should subtract both exponents but remember 2nd exponent is negative so negative times negative = positive

67. anonymous

so just 5 right

68. anonymous

and then you do 2^5 and the answer will be 32

69. Nnesha

no look at the example i gave u exponent was negative at the denomiantor when i moved it to the numerator it becomes positive

70. anonymous

7

71. Nnesha

yes right

72. anonymous

then 2^7=128

73. Nnesha

yes right

74. anonymous

What value of w solves the equation?

75. anonymous

76. anonymous

u there

77. Nnesha

plz make a new post

78. anonymous

What value of w solves the equation?

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