anonymous
  • anonymous
i give metals and i will be your fan. What is the value of the expression 7^3?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
@SolomonZelman @Nnesha
Nnesha
  • Nnesha
the exponents tells how many times you should multiply the base 2^4 = 2 times 2 times 2 times 2
adilalvi
  • adilalvi
343

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More answers

anonymous
  • anonymous
the 4 is a negative
anonymous
  • anonymous
so -343
Nnesha
  • Nnesha
ohh then you should apply the exponent rule \[\huge\rm 7^{-3}\] like this ?
anonymous
  • anonymous
ya
Nnesha
  • Nnesha
\[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction when u flip it , the sign of the exponent would change
adilalvi
  • adilalvi
yaah if its negitive then it will be -343
anonymous
  • anonymous
so \[1/343\]
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
can you help me with more
Nnesha
  • Nnesha
i'll try :=)
anonymous
  • anonymous
What is the value of the expression ? 1/5^-5
anonymous
  • anonymous
|dw:1442438136962:dw|
Nnesha
  • Nnesha
okay apply the same rule!
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction when u flip it , the sign of the exponent would change \(\color{blue}{\text{End of Quote}}\) exponent is negative so ^^^^^^
anonymous
  • anonymous
3125 is the anwser
Nnesha
  • Nnesha
well don't use the calculator.
anonymous
  • anonymous
1/3125
Nnesha
  • Nnesha
no flip the fraction
anonymous
  • anonymous
how can you show me
Nnesha
  • Nnesha
okay if i have \[\huge\rm 2^{-2} =\frac{ 1 }{ 2^2 }\] i would flip the fraction and change the sign of exponent
anonymous
  • anonymous
so it would just be 3125
Nnesha
  • Nnesha
yes right i guess you don't have to find 5^5
Nnesha
  • Nnesha
are there answer choices ?
anonymous
  • anonymous
yes
Nnesha
  • Nnesha
okay then that's right
anonymous
  • anonymous
A. 1/3125 B.1/25 C.25 D.3125
Nnesha
  • Nnesha
ookay. then ur answer is correct :=)
anonymous
  • anonymous
so D
Nnesha
  • Nnesha
yes
anonymous
  • anonymous
What is the value of the expression
Nnesha
  • Nnesha
rewrite 4 in terms of base 2
anonymous
  • anonymous
here are the options
1 Attachment
anonymous
  • anonymous
so 4/3
Nnesha
  • Nnesha
no.. here is an example rewrite 9 in terms of base 3 = 3^2
Nnesha
  • Nnesha
we need to get the same base at the numerator and at the denominator.
anonymous
  • anonymous
OK
anonymous
  • anonymous
2^2=4
Nnesha
  • Nnesha
yes right \[\huge\rm \frac{ 2 }{ (2^2)^{-3} }\] to solve that you need to know two exponent rules first one is \[\huge\rm (x^m)^n=x^{m ยท n}\] and then when we divide same bases we should `subtract` their exponents \[\large\rm \frac{ x^b }{x^c }=x^{b-c}\]
anonymous
  • anonymous
would it be 1/32
Nnesha
  • Nnesha
nope.
Nnesha
  • Nnesha
how did you get that ?
anonymous
  • anonymous
256
Nnesha
  • Nnesha
hmm how ?..
anonymous
  • anonymous
is it right
Nnesha
  • Nnesha
well plz show ur work so i can find where udid a mistake.
anonymous
  • anonymous
plz tell me if it is right or not first
Nnesha
  • Nnesha
well that's a guess
anonymous
  • anonymous
so it is not right is it
anonymous
  • anonymous
128
Nnesha
  • Nnesha
\[\huge\rm (2^2)^{-3}\] we should solve it apply the exponent rule \[\huge\rm (x^m )^n =x^{m \times n}\] multiply the exponents
anonymous
  • anonymous
plz just tell me the answer i only have 2 more minutes to finish it
Nnesha
  • Nnesha
we can solve this in two minutes i can't give u the answer plz try to understand
anonymous
  • anonymous
-64
Nnesha
  • Nnesha
no just multiply the exponents
anonymous
  • anonymous
5
Nnesha
  • Nnesha
\[\huge\rm (2^2)^{-3} =2^{2 \times -3}\] base would stay the same
Nnesha
  • Nnesha
no it's not 5
Nnesha
  • Nnesha
2 times -3 = ?
anonymous
  • anonymous
-6
Nnesha
  • Nnesha
\[\huge\rm \frac{ 2^1 }{ 2^{-6} }\] now subtract the exponent
anonymous
  • anonymous
-5
Nnesha
  • Nnesha
here is an exxample \[\huge\rm \frac{ 3^2 }{ 3^{-3} }=3^{2-(-3)} =3^{2+3}=3^5\]
Nnesha
  • Nnesha
no you should subtract both exponents but remember 2nd exponent is negative so negative times negative = positive
anonymous
  • anonymous
so just 5 right
anonymous
  • anonymous
and then you do 2^5 and the answer will be 32
Nnesha
  • Nnesha
no look at the example i gave u exponent was negative at the denomiantor when i moved it to the numerator it becomes positive
anonymous
  • anonymous
7
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
then 2^7=128
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
What value of w solves the equation?
anonymous
  • anonymous
u there
Nnesha
  • Nnesha
plz make a new post
anonymous
  • anonymous
What value of w solves the equation?

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