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anonymous

  • one year ago

i give metals and i will be your fan. What is the value of the expression 7^3?

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  1. anonymous
    • one year ago
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    @SolomonZelman @Nnesha

  2. Nnesha
    • one year ago
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    the exponents tells how many times you should multiply the base 2^4 = 2 times 2 times 2 times 2

  3. adilalvi
    • one year ago
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    343

  4. anonymous
    • one year ago
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    the 4 is a negative

  5. anonymous
    • one year ago
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    so -343

  6. Nnesha
    • one year ago
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    ohh then you should apply the exponent rule \[\huge\rm 7^{-3}\] like this ?

  7. anonymous
    • one year ago
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    ya

  8. Nnesha
    • one year ago
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    \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction when u flip it , the sign of the exponent would change

  9. adilalvi
    • one year ago
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    yaah if its negitive then it will be -343

  10. anonymous
    • one year ago
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    so \[1/343\]

  11. Nnesha
    • one year ago
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    yes right

  12. anonymous
    • one year ago
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    can you help me with more

  13. Nnesha
    • one year ago
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    i'll try :=)

  14. anonymous
    • one year ago
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    What is the value of the expression ? 1/5^-5

  15. anonymous
    • one year ago
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    |dw:1442438136962:dw|

  16. Nnesha
    • one year ago
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    okay apply the same rule!

  17. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction when u flip it , the sign of the exponent would change \(\color{blue}{\text{End of Quote}}\) exponent is negative so ^^^^^^

  18. anonymous
    • one year ago
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    3125 is the anwser

  19. Nnesha
    • one year ago
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    well don't use the calculator.

  20. anonymous
    • one year ago
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    1/3125

  21. Nnesha
    • one year ago
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    no flip the fraction

  22. anonymous
    • one year ago
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    how can you show me

  23. Nnesha
    • one year ago
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    okay if i have \[\huge\rm 2^{-2} =\frac{ 1 }{ 2^2 }\] i would flip the fraction and change the sign of exponent

  24. anonymous
    • one year ago
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    so it would just be 3125

  25. Nnesha
    • one year ago
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    yes right i guess you don't have to find 5^5

  26. Nnesha
    • one year ago
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    are there answer choices ?

  27. anonymous
    • one year ago
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    yes

  28. Nnesha
    • one year ago
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    okay then that's right

  29. anonymous
    • one year ago
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    A. 1/3125 B.1/25 C.25 D.3125

  30. Nnesha
    • one year ago
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    ookay. then ur answer is correct :=)

  31. anonymous
    • one year ago
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    so D

  32. Nnesha
    • one year ago
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    yes

  33. anonymous
    • one year ago
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    What is the value of the expression

  34. Nnesha
    • one year ago
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    rewrite 4 in terms of base 2

  35. anonymous
    • one year ago
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    here are the options

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  36. anonymous
    • one year ago
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    so 4/3

  37. Nnesha
    • one year ago
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    no.. here is an example rewrite 9 in terms of base 3 = 3^2

  38. Nnesha
    • one year ago
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    we need to get the same base at the numerator and at the denominator.

  39. anonymous
    • one year ago
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    OK

  40. anonymous
    • one year ago
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    2^2=4

  41. Nnesha
    • one year ago
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    yes right \[\huge\rm \frac{ 2 }{ (2^2)^{-3} }\] to solve that you need to know two exponent rules first one is \[\huge\rm (x^m)^n=x^{m · n}\] and then when we divide same bases we should `subtract` their exponents \[\large\rm \frac{ x^b }{x^c }=x^{b-c}\]

  42. anonymous
    • one year ago
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    would it be 1/32

  43. Nnesha
    • one year ago
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    nope.

  44. Nnesha
    • one year ago
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    how did you get that ?

  45. anonymous
    • one year ago
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    256

  46. Nnesha
    • one year ago
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    hmm how ?..

  47. anonymous
    • one year ago
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    is it right

  48. Nnesha
    • one year ago
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    well plz show ur work so i can find where udid a mistake.

  49. anonymous
    • one year ago
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    plz tell me if it is right or not first

  50. Nnesha
    • one year ago
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    well that's a guess

  51. anonymous
    • one year ago
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    so it is not right is it

  52. anonymous
    • one year ago
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    128

  53. Nnesha
    • one year ago
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    \[\huge\rm (2^2)^{-3}\] we should solve it apply the exponent rule \[\huge\rm (x^m )^n =x^{m \times n}\] multiply the exponents

  54. anonymous
    • one year ago
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    plz just tell me the answer i only have 2 more minutes to finish it

  55. Nnesha
    • one year ago
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    we can solve this in two minutes i can't give u the answer plz try to understand

  56. anonymous
    • one year ago
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    -64

  57. Nnesha
    • one year ago
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    no just multiply the exponents

  58. anonymous
    • one year ago
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    5

  59. Nnesha
    • one year ago
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    \[\huge\rm (2^2)^{-3} =2^{2 \times -3}\] base would stay the same

  60. Nnesha
    • one year ago
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    no it's not 5

  61. Nnesha
    • one year ago
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    2 times -3 = ?

  62. anonymous
    • one year ago
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    -6

  63. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 2^1 }{ 2^{-6} }\] now subtract the exponent

  64. anonymous
    • one year ago
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    -5

  65. Nnesha
    • one year ago
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    here is an exxample \[\huge\rm \frac{ 3^2 }{ 3^{-3} }=3^{2-(-3)} =3^{2+3}=3^5\]

  66. Nnesha
    • one year ago
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    no you should subtract both exponents but remember 2nd exponent is negative so negative times negative = positive

  67. anonymous
    • one year ago
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    so just 5 right

  68. anonymous
    • one year ago
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    and then you do 2^5 and the answer will be 32

  69. Nnesha
    • one year ago
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    no look at the example i gave u exponent was negative at the denomiantor when i moved it to the numerator it becomes positive

  70. anonymous
    • one year ago
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    7

  71. Nnesha
    • one year ago
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    yes right

  72. anonymous
    • one year ago
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    then 2^7=128

  73. Nnesha
    • one year ago
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    yes right

  74. anonymous
    • one year ago
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    What value of w solves the equation?

  75. anonymous
    • one year ago
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  76. anonymous
    • one year ago
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    u there

  77. Nnesha
    • one year ago
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    plz make a new post

  78. anonymous
    • one year ago
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    What value of w solves the equation?

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