- anonymous

i give metals and i will be your fan. What is the value of the expression 7^3?

- jamiebookeater

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- anonymous

- Nnesha

the exponents tells how many times you should multiply the base
2^4 = 2 times 2 times 2 times 2

- adilalvi

343

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## More answers

- anonymous

the 4 is a negative

- anonymous

so -343

- Nnesha

ohh then you should apply the exponent rule \[\huge\rm 7^{-3}\] like this ?

- anonymous

ya

- Nnesha

\[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction
when u flip it , the sign of the exponent would change

- adilalvi

yaah if its negitive then it will be -343

- anonymous

so \[1/343\]

- Nnesha

yes right

- anonymous

can you help me with more

- Nnesha

i'll try :=)

- anonymous

What is the value of the expression ? 1/5^-5

- anonymous

|dw:1442438136962:dw|

- Nnesha

okay apply the same rule!

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction
when u flip it , the sign of the exponent would change
\(\color{blue}{\text{End of Quote}}\)
exponent is negative so ^^^^^^

- anonymous

3125 is the anwser

- Nnesha

well don't use the calculator.

- anonymous

1/3125

- Nnesha

no flip the fraction

- anonymous

how can you show me

- Nnesha

okay if i have \[\huge\rm 2^{-2} =\frac{ 1 }{ 2^2 }\] i would flip the fraction and change the sign of exponent

- anonymous

so it would just be 3125

- Nnesha

yes right i guess you don't have to find 5^5

- Nnesha

are there answer choices ?

- anonymous

yes

- Nnesha

okay then that's right

- anonymous

A. 1/3125
B.1/25
C.25
D.3125

- Nnesha

ookay. then ur answer is correct :=)

- anonymous

so D

- Nnesha

yes

- anonymous

What is the value of the expression

- Nnesha

rewrite 4 in terms of base 2

- anonymous

here are the options

##### 1 Attachment

- anonymous

so 4/3

- Nnesha

no..
here is an example
rewrite 9 in terms of base 3 = 3^2

- Nnesha

we need to get the same base at the numerator and at the denominator.

- anonymous

OK

- anonymous

2^2=4

- Nnesha

yes right \[\huge\rm \frac{ 2 }{ (2^2)^{-3} }\]
to solve that you need to know two exponent rules
first one is \[\huge\rm (x^m)^n=x^{m Â· n}\]
and then when we divide same bases we should `subtract` their exponents \[\large\rm \frac{ x^b }{x^c }=x^{b-c}\]

- anonymous

would it be 1/32

- Nnesha

nope.

- Nnesha

how did you get that ?

- anonymous

256

- Nnesha

hmm how ?..

- anonymous

is it right

- Nnesha

well plz show ur work so i can find where udid a mistake.

- anonymous

plz tell me if it is right or not first

- Nnesha

well that's a guess

- anonymous

so it is not right is it

- anonymous

128

- Nnesha

\[\huge\rm (2^2)^{-3}\] we should solve it
apply the exponent rule \[\huge\rm (x^m )^n =x^{m \times n}\] multiply the exponents

- anonymous

plz just tell me the answer i only have 2 more minutes to finish it

- Nnesha

we can solve this in two minutes
i can't give u the answer plz try to understand

- anonymous

-64

- Nnesha

no just multiply the exponents

- anonymous

5

- Nnesha

\[\huge\rm (2^2)^{-3} =2^{2 \times -3}\] base would stay the same

- Nnesha

no it's not 5

- Nnesha

2 times -3 = ?

- anonymous

-6

- Nnesha

\[\huge\rm \frac{ 2^1 }{ 2^{-6} }\] now subtract the exponent

- anonymous

-5

- Nnesha

here is an exxample \[\huge\rm \frac{ 3^2 }{ 3^{-3} }=3^{2-(-3)} =3^{2+3}=3^5\]

- Nnesha

no you should subtract both exponents but remember 2nd exponent is negative so negative times negative = positive

- anonymous

so just 5 right

- anonymous

and then you do 2^5 and the answer will be 32

- Nnesha

no look at the example i gave u
exponent was negative at the denomiantor when i moved it to the numerator it becomes positive

- anonymous

7

- Nnesha

yes right

- anonymous

then 2^7=128

- Nnesha

yes right

- anonymous

What value of w solves the equation?

- anonymous

- anonymous

u there

- Nnesha

plz make a new post

- anonymous

What value of w solves the equation?

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