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anonymous

  • one year ago

simplify: 3i/2+5i

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  1. anonymous
    • one year ago
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    \[\frac{ 3i}{ 2+5i }\]

  2. ganeshie8
    • one year ago
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    Multiply both numerator and denominator by the conjugate of denominator

  3. anonymous
    • one year ago
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    \[\frac{ 3i (2-5i) }{ 2+5i(2-5i) }\] kind of like that right? Just not all over the fraction bar if you know what i mean...

  4. ganeshie8
    • one year ago
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    Yes, if you mean : \(\dfrac{ 3i (2-5i) }{ (2+5i)(2-5i) }\)

  5. anonymous
    • one year ago
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    you're multiplying them right?

  6. ganeshie8
    • one year ago
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    right

  7. ganeshie8
    • one year ago
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    for denominator you may use the identity: \((a+bi)(a-bi)=a^2+b^2\)

  8. anonymous
    • one year ago
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    ok, i understand how to get the top part. you multiply 3i and 2 to get 6i, and 3i and 5i to get 15, and because of the i on both, im pretty sure that it ccancels out. the bottom is where i always get lost

  9. anonymous
    • one year ago
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    oh i see thank you

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