solve by factoring:
x^2 - 2x = 24

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- anonymous

solve by factoring:
x^2 - 2x = 24

- chestercat

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- anonymous

\[^{x^2-2x=24}\]

- anonymous

please help me with this i need to do good on a test tomorrow

- anonymous

Do you have any idea what to do?

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## More answers

- anonymous

um not really, im sorry... i wasnt at school the day of this lesson

- anonymous

1. Make the equation equal to \(0\) first.
Since it is \(x^2-2x=24\), make it equal to zero by SUBTRACTING \(24\) on both sides.|dw:1442444154016:dw|

- anonymous

Do you understand so far?

- anonymous

yes

- anonymous

If you understand it, what would now the equation be?

- anonymous

|dw:1442444340637:dw|

- anonymous

|dw:1442444398863:dw|

- anonymous

Now let's factor this equation. :)
What two numbers will you MULTIPLY to get \(24\)?

- anonymous

6 and 4, right?

- anonymous

6 and 4 are partially correct! But if you add 6 and 4, would you get -2? Yes or no?

- anonymous

so -6?

- anonymous

Yes! -6 and +4 :D

- anonymous

Now solve for x. |dw:1442444656142:dw|

- anonymous

|dw:1442444697995:dw|

- anonymous

ok, i kinda get it but i have a question. if you added 6 and 4, why would you get -2?

- anonymous

When you \(6\) and \(4\) you will not get -2, but you will get 10 because \(\huge 6+4=10\).

- anonymous

But when you add \(-6\) and \(4\), you'll get -2. \(\huge -6+4=-2\)

- anonymous

well yes XD so you're trying to get to -2 as well?

- anonymous

Like that is your goal?

- anonymous

Yes! You want to get -2 when you add them and at the same time get -24 when you multiply them. :D

- anonymous

ohhh, ok that makes sense now...

- anonymous

Okay, back to this. :)
|dw:1442445006629:dw|

- anonymous

Find x. |dw:1442445027766:dw|

- anonymous

so are you now trying to get to -24? so the answer would be x=6,-4?

- anonymous

"so are you now trying to get to -24?" No. We've already done that because \(\huge (-6)(4)=-24\)

- anonymous

"so the answer would be x=6,-4? CORRECT!
We're trying to solve for x. :)

- anonymous

For further references here's a link in factoring trinomials: https://www.youtube.com/watch?v=Nj9GgAM-dTQ
Enjoy Algebra!

- anonymous

oh ok thank you?

- anonymous

!!**

- anonymous

You are welcome! :D

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