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clamin
 one year ago
PLEASE HELP!! MEDAL!!
Am I doing this right??
clamin
 one year ago
PLEASE HELP!! MEDAL!! Am I doing this right??

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Almost, you forgot one thing: \((8i)(3i)=24i^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, unless \(i\) is taken as the imaginary number, i.e. \(i=\sqrt{1}\). If that's the case, then \(i^2=1\), and so \(24i^2=24\).

clamin
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442447580763:dw is this right??

clamin
 one year ago
Best ResponseYou've already chosen the best response.0that was my teacher's work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Same problem here: the last term should be \(7i^2\), or \(7\).

clamin
 one year ago
Best ResponseYou've already chosen the best response.0so the second problem is right?? right?

clamin
 one year ago
Best ResponseYou've already chosen the best response.0im just about the \[i^{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, the second problem is right, but it's missing that squared term. Include that and you're done. \[\begin{align*}4(6i)(7i)(5i)&=24i+(7i)(5+i)\\ &=24i+35i+7i^2\\ &=59i+7i^2\\ &=59i7 \end{align*}\]

clamin
 one year ago
Best ResponseYou've already chosen the best response.0what if you already have negative number and theres \[i ^{2}\]

clamin
 one year ago
Best ResponseYou've already chosen the best response.0for example \[10i ^{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[10i^2=10(1)=10\]
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