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YumYum247
 one year ago
Yelp Me please!!!
YumYum247
 one year ago
Yelp Me please!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F_{net}=ma\] \[F_{applied}F_{f}=m\frac{\Delta v}{t}\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Normally the push force given to me in N but for some odd reason, it's given in velocity(m/sec). How do i change that m/s into N?!?!?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1o it gunna look like this....hold up let me draw!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0They gave you a CHANGE in velocity (from rest to 1.6 m/s) and a time. Use that to find the acceleration and then it's straight Newton's 2nd

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442450685587:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1is it gunna be sec^2???????????????????????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, they don't cancel it's kgm/s², which is a Newton

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ooooooooooooooooooooooooooooooooooooooooooooooooo!! i c

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so 0.72Kg X 0.8m/SEc^2 right

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so from here what do i need to do????????please help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. multiply that to get the net force

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1multiply that by wat tho :"(

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i've already used up all my variables....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1what's left to multiply tho????????/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442451064756:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00.72*0.8 is the right side of the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(F_{applied}  F_f\) is the left side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're solving for \(F_{applied}\)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yes i have the mass (0.72kg) and the 0.8m

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442451193773:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442451186851:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442451340214:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442451278883:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sort of, you should end up adding 4.51 N

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1oh yah i see ....sorry....yah it should have been Ff and not FN
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