#4. I've tried plotting points and I just get a straight line. Not sure if that's right or not.
Here are what I think the transformations are: Right 1, stretch of 3, up 1
Stacey Warren - Expert brainly.com
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Were you able to figure out the domain and range of the transformed graph?
can someone help me i realy need help
No I can't find out the domain or range because none of the points I've plotted correspond to it
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What is the left most point on the given graph?
yes, so the left half of the domain of the original function starts with x = -1
the question is: which x value, when plugged into (1/3)*(x-1), gives a result of -1?
ie what is the solution to (1/3)*(x-1) = -1 ?
this means that the left most part of the domain in the transformed function is x = -2
if you plugged in something smaller than -2 (say -3), then (1/3)*(x-1) produces a number that is smaller than -1 (which is outside the domain of f(x))
the goal is to stay in the domain of f(x) because we can't use x values that aren't defined for f(x)
does that make sense?
Not really. Why would x-values need to be defined for the original function when it's being transformed?
notice how we have f[ `(1/3)*(x-1)` ]
basically f[ T ] where T = (1/3)*(x-1)
is it possible to have f[ T ] when T is say, T = 5 ?
I guess in a way, you have to think backwards
The lowest you can go is T = -1
So you solve for x in T = (1/3)*(x-1) and like you said, you'll get x = -2
So f[ (1/3)*(x-1) ] has the lower part of the domain be x = -2
My final answer is "a."
Hopefully I don't have to graph anything
You don't. They just want the domain and range of the transformed function.