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AdamK
 one year ago
http://imgur.com/RPAkgxB
#4. I've tried plotting points and I just get a straight line. Not sure if that's right or not.
Here are what I think the transformations are: Right 1, stretch of 3, up 1
AdamK
 one year ago
http://imgur.com/RPAkgxB #4. I've tried plotting points and I just get a straight line. Not sure if that's right or not. Here are what I think the transformations are: Right 1, stretch of 3, up 1

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Were you able to figure out the domain and range of the transformed graph?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can someone help me i realy need help

AdamK
 one year ago
Best ResponseYou've already chosen the best response.0No I can't find out the domain or range because none of the points I've plotted correspond to it

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1What is the left most point on the given graph?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes, so the left half of the domain of the original function starts with x = 1 the question is: which x value, when plugged into (1/3)*(x1), gives a result of 1? ie what is the solution to (1/3)*(x1) = 1 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1this means that the left most part of the domain in the transformed function is x = 2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1if you plugged in something smaller than 2 (say 3), then (1/3)*(x1) produces a number that is smaller than 1 (which is outside the domain of f(x))

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the goal is to stay in the domain of f(x) because we can't use x values that aren't defined for f(x)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1does that make sense?

AdamK
 one year ago
Best ResponseYou've already chosen the best response.0Not really. Why would xvalues need to be defined for the original function when it's being transformed?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1notice how we have f[ `(1/3)*(x1)` ] basically f[ T ] where T = (1/3)*(x1)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1is it possible to have f[ T ] when T is say, T = 5 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I guess in a way, you have to think backwards

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1The lowest you can go is T = 1 So you solve for x in T = (1/3)*(x1) and like you said, you'll get x = 2 So f[ (1/3)*(x1) ] has the lower part of the domain be x = 2

AdamK
 one year ago
Best ResponseYou've already chosen the best response.0Hopefully I don't have to graph anything

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1You don't. They just want the domain and range of the transformed function.
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