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anonymous

  • one year ago

If g(x)= 4+ x+ e^x, find g^-1 (5)

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  1. geerky42
    • one year ago
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    HINT: \(g(0) = 5\)

  2. Empty
    • one year ago
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    Even though this is totally beyond the scope of the question, you can algebraically invert this function.

  3. Empty
    • one year ago
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    Ok sorry sasha don't look cause this won't help you, sorry. \[x=4+y+e^y\]\[x-4 = y+e^y\]\[e^{x-4} = e^ye^{e^y}\]\[W(e^{x-4}) = e^y\]\[\ln [W(e^{x-4})] = y\] We could stop here but this is kind of ugly I think so let's rearrange this identity for Lambert W: \[W(x)e^{W(x)} = x\]\[\ln[W(x)] +W(x)=\ln x\] So I can rewrite y now as: \[y=x-4-W(e^{x-4})\] I like this more, and we can go ahead and plug in x=5 now like they ask in the problem to get: \[y(5)=5-4-W(e)=\] So this is kinda cute and fun since this is the general solution to a problem most people think isn't solvable with algebra.

  4. zzr0ck3r
    • one year ago
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    lol @sasha.o do you get the first hint? if \(f(a)=b\) then \(f^{-1}(b)=a\)

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