MEDALS PLEASE HELP!!
Please subtract and simplify
4y/y^2-6y+8 - 16/y^2-6y+8

- anonymous

MEDALS PLEASE HELP!!
Please subtract and simplify
4y/y^2-6y+8 - 16/y^2-6y+8

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

\[\frac{ 4_{y} }{ y ^{2}-6_{y}+8 } - \frac{ 16 }{ y ^{2}-6_{y}+8 }\]
This right?

- anonymous

Yes

- anonymous

Since the denominators are exactly the same, wouldn't the equation just be
\[\frac{ 4_{y} -16 }{ y ^{2}-6_{y} + 8}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

It told me it has to be simplified down

- anonymous

rheaanderson341 is correct ^

- anonymous

So the correct answer is 4y-16/y^2-6y+8 ???

- anonymous

No, it still can be simplified. You can simplify the \[4_{y} and 6_{y}\] along with the 16 and 8.

- anonymous

\[4\div(y-2) simplified\]

- anonymous

|dw:1442451532151:dw|

- anonymous

(y-4) cancels out on top and bottom

- anonymous

So its 4/y-2 right?

- anonymous

yeah

- anonymous

Wow! I forgot about that method. What's it called again, @mshaw24 ?

- anonymous

I understand that now! Thank you so much! Do you by any chance know anythinf about finding the real zeros of a function

- anonymous

Its just expanding out the polynomial on the bottom and then cancelling it out

- anonymous

Possibly its been a while since ive done it. whats the question

- anonymous

F(x)= x^3 +4x^2+x-6

- anonymous

It says there is 3 real zeros

- anonymous

so when finding zeros, you have the amount as the highest power. IE x^3 = 3 real zeros as to finding them set the equation = to zero and solve.

- anonymous

\[x(x ^{2}+4x+1) = 6\]

- anonymous

zeros are x=6 and then expand out the polynomial

- anonymous

hang on solving it now

- anonymous

Okay thank you!

- anonymous

Have you learned quadratic formula?

- anonymous

Yes

- anonymous

\[\frac{ -B+-\sqrt{B ^{2}-4AC} }{ 2A }\]

- anonymous

use this and it gives you -0.2679 and -3.732 plus 6 from above. i think these are your answers

- anonymous

Would i have to round those answers because it keeps telling me its incorrect?

- anonymous

try \[4+\sqrt{3}\] and [4-\sqrt{3}\]

- anonymous

if its not that then I am not sure. It might have been a simple mistake, but like i said its been a while

- anonymous

Its still telling me no, ill have to research how to do it, thank for all of your help. Do you mind helping me with one final question?

- anonymous

I actually have to get to bed. Sorry i have early classes haha best of luck to you

Looking for something else?

Not the answer you are looking for? Search for more explanations.