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anonymous
 one year ago
MEDALS PLEASE HELP!!
Please subtract and simplify
4y/y^26y+8  16/y^26y+8
anonymous
 one year ago
MEDALS PLEASE HELP!! Please subtract and simplify 4y/y^26y+8  16/y^26y+8

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4_{y} }{ y ^{2}6_{y}+8 }  \frac{ 16 }{ y ^{2}6_{y}+8 }\] This right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since the denominators are exactly the same, wouldn't the equation just be \[\frac{ 4_{y} 16 }{ y ^{2}6_{y} + 8}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It told me it has to be simplified down

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0rheaanderson341 is correct ^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the correct answer is 4y16/y^26y+8 ???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, it still can be simplified. You can simplify the \[4_{y} and 6_{y}\] along with the 16 and 8.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[4\div(y2) simplified\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442451532151:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(y4) cancels out on top and bottom

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wow! I forgot about that method. What's it called again, @mshaw24 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand that now! Thank you so much! Do you by any chance know anythinf about finding the real zeros of a function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its just expanding out the polynomial on the bottom and then cancelling it out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Possibly its been a while since ive done it. whats the question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It says there is 3 real zeros

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so when finding zeros, you have the amount as the highest power. IE x^3 = 3 real zeros as to finding them set the equation = to zero and solve.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x(x ^{2}+4x+1) = 6\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0zeros are x=6 and then expand out the polynomial

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hang on solving it now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Have you learned quadratic formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ B+\sqrt{B ^{2}4AC} }{ 2A }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0use this and it gives you 0.2679 and 3.732 plus 6 from above. i think these are your answers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would i have to round those answers because it keeps telling me its incorrect?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0try \[4+\sqrt{3}\] and [4\sqrt{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if its not that then I am not sure. It might have been a simple mistake, but like i said its been a while

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its still telling me no, ill have to research how to do it, thank for all of your help. Do you mind helping me with one final question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I actually have to get to bed. Sorry i have early classes haha best of luck to you
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