anonymous
  • anonymous
MEDALS PLEASE HELP!! Please subtract and simplify 4y/y^2-6y+8 - 16/y^2-6y+8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\frac{ 4_{y} }{ y ^{2}-6_{y}+8 } - \frac{ 16 }{ y ^{2}-6_{y}+8 }\] This right?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Since the denominators are exactly the same, wouldn't the equation just be \[\frac{ 4_{y} -16 }{ y ^{2}-6_{y} + 8}\]

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anonymous
  • anonymous
It told me it has to be simplified down
anonymous
  • anonymous
rheaanderson341 is correct ^
anonymous
  • anonymous
So the correct answer is 4y-16/y^2-6y+8 ???
anonymous
  • anonymous
No, it still can be simplified. You can simplify the \[4_{y} and 6_{y}\] along with the 16 and 8.
anonymous
  • anonymous
\[4\div(y-2) simplified\]
anonymous
  • anonymous
|dw:1442451532151:dw|
anonymous
  • anonymous
(y-4) cancels out on top and bottom
anonymous
  • anonymous
So its 4/y-2 right?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
Wow! I forgot about that method. What's it called again, @mshaw24 ?
anonymous
  • anonymous
I understand that now! Thank you so much! Do you by any chance know anythinf about finding the real zeros of a function
anonymous
  • anonymous
Its just expanding out the polynomial on the bottom and then cancelling it out
anonymous
  • anonymous
Possibly its been a while since ive done it. whats the question
anonymous
  • anonymous
F(x)= x^3 +4x^2+x-6
anonymous
  • anonymous
It says there is 3 real zeros
anonymous
  • anonymous
so when finding zeros, you have the amount as the highest power. IE x^3 = 3 real zeros as to finding them set the equation = to zero and solve.
anonymous
  • anonymous
\[x(x ^{2}+4x+1) = 6\]
anonymous
  • anonymous
zeros are x=6 and then expand out the polynomial
anonymous
  • anonymous
hang on solving it now
anonymous
  • anonymous
Okay thank you!
anonymous
  • anonymous
Have you learned quadratic formula?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
\[\frac{ -B+-\sqrt{B ^{2}-4AC} }{ 2A }\]
anonymous
  • anonymous
use this and it gives you -0.2679 and -3.732 plus 6 from above. i think these are your answers
anonymous
  • anonymous
Would i have to round those answers because it keeps telling me its incorrect?
anonymous
  • anonymous
try \[4+\sqrt{3}\] and [4-\sqrt{3}\]
anonymous
  • anonymous
if its not that then I am not sure. It might have been a simple mistake, but like i said its been a while
anonymous
  • anonymous
Its still telling me no, ill have to research how to do it, thank for all of your help. Do you mind helping me with one final question?
anonymous
  • anonymous
I actually have to get to bed. Sorry i have early classes haha best of luck to you

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