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anonymous

  • one year ago

MEDALS PLEASE HELP!! Please subtract and simplify 4y/y^2-6y+8 - 16/y^2-6y+8

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  1. anonymous
    • one year ago
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    \[\frac{ 4_{y} }{ y ^{2}-6_{y}+8 } - \frac{ 16 }{ y ^{2}-6_{y}+8 }\] This right?

  2. anonymous
    • one year ago
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    Yes

  3. anonymous
    • one year ago
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    Since the denominators are exactly the same, wouldn't the equation just be \[\frac{ 4_{y} -16 }{ y ^{2}-6_{y} + 8}\]

  4. anonymous
    • one year ago
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    It told me it has to be simplified down

  5. anonymous
    • one year ago
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    rheaanderson341 is correct ^

  6. anonymous
    • one year ago
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    So the correct answer is 4y-16/y^2-6y+8 ???

  7. anonymous
    • one year ago
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    No, it still can be simplified. You can simplify the \[4_{y} and 6_{y}\] along with the 16 and 8.

  8. anonymous
    • one year ago
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    \[4\div(y-2) simplified\]

  9. anonymous
    • one year ago
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    |dw:1442451532151:dw|

  10. anonymous
    • one year ago
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    (y-4) cancels out on top and bottom

  11. anonymous
    • one year ago
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    So its 4/y-2 right?

  12. anonymous
    • one year ago
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    yeah

  13. anonymous
    • one year ago
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    Wow! I forgot about that method. What's it called again, @mshaw24 ?

  14. anonymous
    • one year ago
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    I understand that now! Thank you so much! Do you by any chance know anythinf about finding the real zeros of a function

  15. anonymous
    • one year ago
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    Its just expanding out the polynomial on the bottom and then cancelling it out

  16. anonymous
    • one year ago
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    Possibly its been a while since ive done it. whats the question

  17. anonymous
    • one year ago
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    F(x)= x^3 +4x^2+x-6

  18. anonymous
    • one year ago
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    It says there is 3 real zeros

  19. anonymous
    • one year ago
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    so when finding zeros, you have the amount as the highest power. IE x^3 = 3 real zeros as to finding them set the equation = to zero and solve.

  20. anonymous
    • one year ago
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    \[x(x ^{2}+4x+1) = 6\]

  21. anonymous
    • one year ago
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    zeros are x=6 and then expand out the polynomial

  22. anonymous
    • one year ago
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    hang on solving it now

  23. anonymous
    • one year ago
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    Okay thank you!

  24. anonymous
    • one year ago
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    Have you learned quadratic formula?

  25. anonymous
    • one year ago
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    Yes

  26. anonymous
    • one year ago
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    \[\frac{ -B+-\sqrt{B ^{2}-4AC} }{ 2A }\]

  27. anonymous
    • one year ago
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    use this and it gives you -0.2679 and -3.732 plus 6 from above. i think these are your answers

  28. anonymous
    • one year ago
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    Would i have to round those answers because it keeps telling me its incorrect?

  29. anonymous
    • one year ago
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    try \[4+\sqrt{3}\] and [4-\sqrt{3}\]

  30. anonymous
    • one year ago
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    if its not that then I am not sure. It might have been a simple mistake, but like i said its been a while

  31. anonymous
    • one year ago
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    Its still telling me no, ill have to research how to do it, thank for all of your help. Do you mind helping me with one final question?

  32. anonymous
    • one year ago
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    I actually have to get to bed. Sorry i have early classes haha best of luck to you

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