Simplified version of x+2/y-3 + 3x-1/y-3.... is the corrrect answer 4x+1/y-3 ??? Medals

- anonymous

Simplified version of x+2/y-3 + 3x-1/y-3.... is the corrrect answer 4x+1/y-3 ??? Medals

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- schrodinger

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- jim_thompson5910

the original expression is this right?
\[\Large \frac{x+2}{y+3} + \frac{3x-1}{y+3}\]

- anonymous

Yes

- anonymous

ya thats right

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## More answers

- jim_thompson5910

you have the correct answer assuming you meant to write \[\Large \frac{4x+1}{y+3}\]

- jim_thompson5910

sorry for some reason, I wrote "y+3" when it should be "y-3". My bad

- anonymous

Thank you both!! And its okay thank you for your help!

- jim_thompson5910

no problem

- anonymous

Did i get this one right too? 3/x+1 + 4/x+1.... the answer is 7/x+1 ??

- jim_thompson5910

yes you did

- jim_thompson5910

Nice job

- jim_thompson5910

use parenthesis to indicate you are dividing by all of "x+1"
`3/x+1` is NOT the same as `3/(x+1)`

- jim_thompson5910

\[\Large 3/x + 1 = \frac{3}{x} + 1\]
\[\Large 3/(x + 1) = \frac{3}{x+1}\]

- anonymous

Im so sorry I didn't know! I'm new to this so I'm learning

- jim_thompson5910

that's ok

- anonymous

Am i correct for this problem also?
5x^2 - x(x-3)
= 4x^2- 3x ??

- jim_thompson5910

you distributed incorrectly

- jim_thompson5910

|dw:1442454918377:dw|

- jim_thompson5910

|dw:1442454929560:dw|

- anonymous

Oh okay! So it would be 4x^2+ 3x

- jim_thompson5910

yes

- anonymous

Also could you help me with a problem that I have no idea how to do? Its x-{-x+[-x-(x-1)]}

- jim_thompson5910

let's work from the inside and work our way outward

- jim_thompson5910

what is -(x-1) equal to?

- anonymous

-x+1 ?

- jim_thompson5910

good

- jim_thompson5910

replace the `-(x-1)` with `-x+1`
and we go from this `x-{-x+[-x-(x-1)]}` to this `x-{-x+[-x-x+1]}`

- anonymous

Okay now where to from there?

- jim_thompson5910

-x-x+1 simplifies to ???

- anonymous

-x^2 +1 ??

- jim_thompson5910

no

- jim_thompson5910

you might be thinking of -x times x
but instead it's -x minus x

- anonymous

0?

- jim_thompson5910

not quite

- jim_thompson5910

what is -1 -1 equal to

- anonymous

-2

- jim_thompson5910

think of it as
I'm 1 dollar in debt. I spend another dollar. How much am I in debt?

- jim_thompson5910

yes 2 dollars in debt, so -2

- jim_thompson5910

similarly, -x-x = -2x

- anonymous

Oh okay

- jim_thompson5910

IF it was x-x, then yes it would be 0x = 0
but that first x isn't positive

- anonymous

I understand that part so now what do i solve?

- jim_thompson5910

so you agree that `x-{-x+[-x-x+1]}` becomes `x-{-x+[-2x+1]}`

- anonymous

Yes :)

- jim_thompson5910

the square brackets aren't doing anything so we can drop them
`x-{-x+[-2x+1]}` turns into `x-{-x-2x+1}`

- anonymous

Alright

- jim_thompson5910

what would -x-2x+1 simplify to?

- anonymous

-3x+1 ??

- jim_thompson5910

yep

- jim_thompson5910

we now have x-{-3x+1}

- jim_thompson5910

what's next?

- anonymous

Would it be 3x^2 -x ???

- jim_thompson5910

maybe think of it as x-1*(-3x+1)

- anonymous

Help?

- jim_thompson5910

distribute the -1 through. Do you know how?

- anonymous

3x-1 ???

- jim_thompson5910

|dw:1442456228637:dw|

- jim_thompson5910

yes
|dw:1442456250110:dw|

- jim_thompson5910

x-{-3x+1} turns into x+3x-1

- anonymous

So would the answer be 4x-1 ??

- jim_thompson5910

yep

- anonymous

Omg thank you so much for everything!!!

- jim_thompson5910

no problem

- anonymous

3x(x-2) -4x^2
= -x^2 -6x
right?

- jim_thompson5910

correct

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