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anonymous
 one year ago
Evaluate the integral
anonymous
 one year ago
Evaluate the integral

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does it help to know that \[1\sin^2(x)=\cos^2(x)\]?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1how about this? \[\Large \frac{\sin(x)}{1\sin^2(x)}\] \[\Large \frac{\sin(x)}{\cos^2(x)}\] \[\Large \frac{\sin(x)}{\cos(x)*\cos(x)}\] \[\Large \frac{1}{\cos(x)}*\frac{\sin(x)}{\cos(x)}\] \[\Large \sec(x)*\tan(x)\] does that help?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes because the derivative of sec(x) is sec(x)*tan(x)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so you have to think backwards in a way
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