## anonymous one year ago Evaluate the integral

1. anonymous
2. anonymous

does it help to know that $1-\sin^2(x)=\cos^2(x)$?

3. anonymous

Not really

4. jim_thompson5910

how about this? $\Large \frac{\sin(x)}{1-\sin^2(x)}$ $\Large \frac{\sin(x)}{\cos^2(x)}$ $\Large \frac{\sin(x)}{\cos(x)*\cos(x)}$ $\Large \frac{1}{\cos(x)}*\frac{\sin(x)}{\cos(x)}$ $\Large \sec(x)*\tan(x)$ does that help?

5. anonymous

6. jim_thompson5910

yes because the derivative of sec(x) is sec(x)*tan(x)

7. jim_thompson5910

so you have to think backwards in a way

8. anonymous

Yeah, I got it.