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Lena772
 one year ago
Carboxylic acids are organic acids that contain the COOH group. A monoprotic Carboxylic Acid (0.5899 g) is neutralized with 48.4 mL 0.0998 M NaOH. What is the Molar Mass (in grams / mole) of the Carboxlyic Acid?
Lena772
 one year ago
Carboxylic acids are organic acids that contain the COOH group. A monoprotic Carboxylic Acid (0.5899 g) is neutralized with 48.4 mL 0.0998 M NaOH. What is the Molar Mass (in grams / mole) of the Carboxlyic Acid?

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Lena772
 one year ago
Best ResponseYou've already chosen the best response.048.4mL = 0.0484 L 0.484 L * 0.0998 M = mol solute 0.0483032 = mol solute MM= g/mol 0.5899g/ 0.0483032mol = 12.21 g/mol. I got it wrong however.

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0@Photon336 @Elsa213 @aaronq

Elsa213
 one year ago
Best ResponseYou've already chosen the best response.0"Ste[p 1: a balanced equation. HCOOH + NaOH > NaCOO + HOH Step 2: Write what you know under the equation. XCOOH + NaOH > NaCOO + HOH m = 0.5899 g v = 48.4 mL M = ? C = 0.0998 mol/L Step 3: Convert the Vol and Conc into moles of NaOH moles of NaOH = 0.0998 mol/L x 48.4 mL = 4.83 millimoles STep 4: Compare the moles of COOH to moles of NaOH from the equation. It is 1 to 1 so every mole of NaOH needs the same number of moles of COOH therefore moles of COOH is 4.83 millimoles. Step 5: Now that you have a mass and number of moles of COOH you can calculate M M = grams / moles 0.5899 g / 0.00483 mol = 122 .13 g/mol"

Elsa213
 one year ago
Best ResponseYou've already chosen the best response.0https://answers.yahoo.com/question/index?qid=20111120183255AAWLaFY ;o

Elsa213
 one year ago
Best ResponseYou've already chosen the best response.0Hopefully that helped :3
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