sissyedgar
  • sissyedgar
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the distance in 4.5 h. Car B traveled 5 mph slower than Car A. How fast did Car B travel? mph
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
i hate word problems don't you?
sissyedgar
  • sissyedgar
Yass!
anonymous
  • anonymous
distance is rate times time, so \[D=4\times R=4.5\times( R-5)\]

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More answers

anonymous
  • anonymous
we can solve \[4R=4.5(R-5)\] for R
sissyedgar
  • sissyedgar
wait 1 sec...
sissyedgar
  • sissyedgar
R = 45 rite?
anonymous
  • anonymous
yeah! but we are not done
sissyedgar
  • sissyedgar
mk
anonymous
  • anonymous
i had \(R\) as the rate of the faster car, so the rate of the slower car is \(45-5=40\)
sissyedgar
  • sissyedgar
right! Ty Satellite!
anonymous
  • anonymous
yw

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