The set {-1,0,1} is not closed under which operation?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

The set {-1,0,1} is not closed under which operation?

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

you got any idea what this means?
Not really, this is completely new to me.
that is what thought closed under addition for example would mean if you add any two of those you get another one of those

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

that is not true, since \(1+1=2\) and \(2\) is not in your set
it also not closed under multiplication since \(1\div 0\) is not a number
DIvision or subtraction then?
addition, not closed division, not closed subtraction, not close since \(-1-1=-2\)
it is closed under multiplication though
Multiplication Subtraction Division all of the above is what I have for answers
hmm the last two, but that is not a choice it is closed under multiplication, not subtraction or division
Oh no..
certainly it is not closed under division because you cannot ever divide by zero but it is also not closed under subtraction what is this, some FLVS question?
Its a stupid question. thats what it is lol Which one would you choose?
i guess i would choose "division" but it really says "not closed" right?
if you multiply any two of those you get another one of those for sure
It does say not closed!
so it is closed under multiplication don't choose "all of the above"
ok pick division i guess and write them and tell them it is a mistake on line class?
Yeah! I'll tell them!
what system?
Could you help me with one more?
sure i can try
wava k12
i thought they new better in washington

Not the answer you are looking for?

Search for more explanations.

Ask your own question