Prove that both trapezoid rule and Simpson's rule give an estimate within 0.005 of true value of integral?

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Using Maple I've found:
trapezoid rule gives 2.432066146
Simpson's rule gives 2.430797145

\[\int\limits_{a}^{b}\frac{ x^2 }{ \sqrt{(1-x^2)(k^2-x^2)} }\]
a = 3
b = 5
k = 2

@SolomonZelman
@pooja195

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.