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can someone help me? i will medal

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what do you need help with?
ok first let me send the the question the the graph that goes with it on a screen shot
http://prntscr.com/8h87um

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Other answers:

http://prntscr.com/8h87um
I would need to take a look at problem # 1.5. This question alone does not make much sense.
i sent a screen shot of problem 1.5 the second time
They are the same screenshots. Try again :-)
http://prntscr.com/8h88xr
ok lets give it a try. First measure the size of 7th grade and 8th grade thermometer and post it here. Measure it with a ruler/scale if you can.
7th grade is 1/3 bigger
before we continue, is there something else that is written in the question in 1.5 or is it just the diagram?
just a diagram
ok give me 1-2 minute to think on it.
So the way i am thinking of is that you first measure the height of both seventh and eighth grade thermometer using a ruler/scale. Then measure the height of eighth grade thermometer till the 10 day mark. Do this far and then we will continue.
the next step is to multiply the height of seventh grade thermometer with the height of eight grade thermometer till the 10 day mark and then divide the whole thing by the full height of eight grade thermometer. This new value will be the new height of your 10 day mark for eighth grade thermometer.

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