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anonymous

  • one year ago

can someone help me? i will medal

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  1. abdullah1995
    • one year ago
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    what do you need help with?

  2. anonymous
    • one year ago
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    ok first let me send the the question the the graph that goes with it on a screen shot

  3. anonymous
    • one year ago
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    http://prntscr.com/8h87um

  4. anonymous
    • one year ago
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    http://prntscr.com/8h87um

  5. abdullah1995
    • one year ago
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    I would need to take a look at problem # 1.5. This question alone does not make much sense.

  6. anonymous
    • one year ago
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    i sent a screen shot of problem 1.5 the second time

  7. abdullah1995
    • one year ago
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    They are the same screenshots. Try again :-)

  8. anonymous
    • one year ago
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    http://prntscr.com/8h88xr

  9. abdullah1995
    • one year ago
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    ok lets give it a try. First measure the size of 7th grade and 8th grade thermometer and post it here. Measure it with a ruler/scale if you can.

  10. anonymous
    • one year ago
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    7th grade is 1/3 bigger

  11. abdullah1995
    • one year ago
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    before we continue, is there something else that is written in the question in 1.5 or is it just the diagram?

  12. anonymous
    • one year ago
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    just a diagram

  13. abdullah1995
    • one year ago
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    ok give me 1-2 minute to think on it.

  14. abdullah1995
    • one year ago
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    So the way i am thinking of is that you first measure the height of both seventh and eighth grade thermometer using a ruler/scale. Then measure the height of eighth grade thermometer till the 10 day mark. Do this far and then we will continue.

  15. abdullah1995
    • one year ago
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    the next step is to multiply the height of seventh grade thermometer with the height of eight grade thermometer till the 10 day mark and then divide the whole thing by the full height of eight grade thermometer. This new value will be the new height of your 10 day mark for eighth grade thermometer.

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