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anonymous
 one year ago
STuck? if cartesian equation of x= sint, y=cos^2t is = x^2 + y = 1... how does the graph in the range of 2pi <t<2pi end up being an upside down parabola with values that go beyond 1 and 1?
anonymous
 one year ago
STuck? if cartesian equation of x= sint, y=cos^2t is = x^2 + y = 1... how does the graph in the range of 2pi <t<2pi end up being an upside down parabola with values that go beyond 1 and 1?

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BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1is you r question, the graph being a parabola or having a range beyond 1 and 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442467120251:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So am I trying to graph with incorrect points or is my graph correct?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1yes its clear that x can only take values between 1 and 1 since \(1\leq \sin(t) \leq 1\) so your graph is correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if my professor asked me to identify the behavior of the graph according to the cartesian equation I derived from these x and y functions... I could tell him that a particle traveling along the path of this graph would actually travel clockwise then bounce back and travel counterclockwise between the 1 and 1 on the xaxis..???? does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because thats' mainly my thing, Im trying to understand the behavior of how a particle would travel along this path. starting at 2pi and ending at 2pi.. and since my graph starts and ends at 1 and 1... would my conclusion be correct? (about the bouncing back and forth)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you still there?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1yes the idea of travelling is derived from the time  t So if we take the distance on x direction, the relationship of that with the time is given as \(x = \sin(t)\) so there itself it says that the x change in a oscillatory way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. fantastic!!!!!!! thank you. I just wanted to make sure I was on the right track. And you seem pretty confident. :) Thank you very much.

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1here what desmos.com give
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