anonymous
  • anonymous
STuck? if cartesian equation of x= sint, y=cos^2t is = x^2 + y = 1... how does the graph in the range of -2pi
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
BAdhi
  • BAdhi
is you r question, the graph being a parabola or having a range beyond -1 and 1?
anonymous
  • anonymous
|dw:1442467120251:dw|
anonymous
  • anonymous
So am I trying to graph with incorrect points or is my graph correct?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

BAdhi
  • BAdhi
yes its clear that x can only take values between -1 and 1 since \(-1\leq \sin(t) \leq 1\) so your graph is correct
anonymous
  • anonymous
so if my professor asked me to identify the behavior of the graph according to the cartesian equation I derived from these x and y functions... I could tell him that a particle traveling along the path of this graph would actually travel clockwise then bounce back and travel counterclockwise between the -1 and 1 on the x-axis..???? does that make sense?
anonymous
  • anonymous
because thats' mainly my thing, Im trying to understand the behavior of how a particle would travel along this path. starting at -2pi and ending at 2pi.. and since my graph starts and ends at -1 and 1... would my conclusion be correct? (about the bouncing back and forth)
anonymous
  • anonymous
are you still there?
BAdhi
  • BAdhi
yes the idea of travelling is derived from the time - t So if we take the distance on x direction, the relationship of that with the time is given as \(x = \sin(t)\) so there itself it says that the x change in a oscillatory way
anonymous
  • anonymous
ok. fantastic!!!!!!! thank you. I just wanted to make sure I was on the right track. And you seem pretty confident. :) Thank you very much.
BAdhi
  • BAdhi
you are welcome
BAdhi
  • BAdhi
here what desmos.com give
1 Attachment

Looking for something else?

Not the answer you are looking for? Search for more explanations.