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anonymous

  • one year ago

PLEASE HELPP MEDALLS. What are the roots of -12x^2+11x-3=0

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  1. zzr0ck3r
    • one year ago
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    you can complete the square or use the quadratic formula

  2. zzr0ck3r
    • one year ago
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    do you know how to do either?

  3. anonymous
    • one year ago
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    Yeah let me try the quadratic formula and see if i get the right answer

  4. anonymous
    • one year ago
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    Yeah...idk how to do it.

  5. zzr0ck3r
    • one year ago
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    \(ax^2+bx+c=0 \iff x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \) for you \[a=-12 \\ b=11\\c=-3\]

  6. anonymous
    • one year ago
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    Yeah i got that ..but the answer choices have the letter i in them and idk where the i comes from

  7. anonymous
    • one year ago
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    oh that is complex numbers used when you get negative square root

  8. anonymous
    • one year ago
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    Would the answer be -11 plus or negative i×square root of 15 over 12?

  9. anonymous
    • one year ago
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    I meant square root of 23 over 24

  10. anonymous
    • one year ago
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    basically \[i = \sqrt{-1}\]

  11. anonymous
    • one year ago
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    \[e.g.\sqrt{-11}=\sqrt{11}i\]

  12. anonymous
    • one year ago
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    I understand thank you!

  13. anonymous
    • one year ago
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    no worries :)

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spraguer (Moderator)
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