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anonymous

  • one year ago

tennisball mashine shoots a ball straight up in the air, it lands after 7 seconds What's the hight of the ball given v=f(t)=30-10t i figured that the equation i got is actually the derivative of -5t^2+30t ball shots upp with a velocity of 30m/s, is a physics mix i have no pheta angle neede to solve it in a simpler way...vertex apex im asked: what does 30 stand for? -10t?acceleration? and what's max height? i have a graf with and dowsslopping linear line crossing the y axis at 30m/s and the x axis at 3 seconds

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  1. anonymous
    • one year ago
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    ok tell me V=30-10t did they give you this with question

  2. anonymous
    • one year ago
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    oh ok now i can solve it

  3. anonymous
    • one year ago
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    is the answer 35 feet

  4. anonymous
    • one year ago
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    because you just sub 7 into original equation and you will get maximum height

  5. anonymous
    • one year ago
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    \[=-5(7)^{2}+30 \times 7\]

  6. IrishBoy123
    • one year ago
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    yes, for \(v(t) =30 - 10t\) we have 30 as initial velocity, -10 for gravity (acceleration) so as you say \(x(t) =30t - 5t^2+x_0 = 5t(6-t)+x_0\) but note the integration constant if it lands after t = 7, then \(\large x(7) = x_0-35\) !!!!! weird! is the machine 35m above gound or does the ball land in a crater?!?! anyways, at the peak of its flight \(v(t) = 0 \implies 30 - 10t=0, t = 3\) solve from there

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