anonymous
  • anonymous
F(x)=ln(x) g(x)=e^x+1. F(g(x)) must then be ln(e^x+1) right? Can you simplify this?
Calculus1
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
dumbcow
  • dumbcow
is that e^(x+1) ?
dumbcow
  • dumbcow
e^x and ln(x) are inverse functions so: \[\ln(e^x) = x\]
anonymous
  • anonymous
yes you are right

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
No, g(x) is just e^x+1, as if it was 1+e^x without any parenthesis
anonymous
  • anonymous
\[f(g(x))= \ln(e ^{x}+1)\]
anonymous
  • anonymous
let me know if u need furthur help :)
anonymous
  • anonymous
oh btw you cant simplify further
anonymous
  • anonymous
or maybe write Near x=0, I suppose you could expand e^x,
anonymous
  • anonymous
because ln(1) = 0 and also ln(e^x) is also 0 because they are inverse pairs
anonymous
  • anonymous
So that makes it x+1 in the end. But the reverse, g(f(x)) = e^ln(x)+1 will also become x+1? Right?
anonymous
  • anonymous
Ah, ok :)
anonymous
  • anonymous
|dw:1442478053901:dw|
anonymous
  • anonymous
yes
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
no problem just tag if you need any further help :)
anonymous
  • anonymous
srry ln(e^x)= x not zero

Looking for something else?

Not the answer you are looking for? Search for more explanations.