## anonymous one year ago f(x)=ln(x)+e^(1/x-1). What´s the domain for f? Any suggestions on where to start? :)

1. anonymous

since the function f(x) has two distinct parts, you should start with them and then find the intersection of the two individual domains, like for Ln(x) the domain would be_

2. amistre64

*union of them

3. zzr0ck3r

You have two things to worry about $$x>0$$ because of the domain of $$\ln(x)$$ and $$x-1\ne 0$$ because of the $$\dfrac{1}{x-1}$$ (we cant divide by $$0$$). So we can use all positive numbers except $$1$$. Domain is $$\{x\mid x>0\text{ and } x\ne 1\}=(0,1)\cup (1,\infty)$$ Make sense?

4. amistre64

hmm, might be looking at it in a mirror tho ... the union of the bad parts that is

5. anonymous

Yes, it makes totally sense! Thanks!

6. zzr0ck3r

np

7. zzr0ck3r

I think we want the intersection of the two @amistre64

8. anonymous

np? :)

9. zzr0ck3r

no problem @Wikis

10. anonymous

Of course XD Thought it was a math term that I had missed :D

11. amistre64

intersection of the domains yes ... i was thinking about the exclusions at first. we want to make sure all the bad parts are avoided for each term

12. amistre64

if x=2,3 are bad for the first part, and x=2,4,5 are bad for the last part; then we would exclude x=2,3,4,5 was in my head

13. amistre64

time to build a house ... have fun