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anonymous

  • one year ago

f(x)=ln(x)+e^(1/x-1). What´s the domain for f? Any suggestions on where to start? :)

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  1. anonymous
    • one year ago
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    since the function f(x) has two distinct parts, you should start with them and then find the intersection of the two individual domains, like for Ln(x) the domain would be_

  2. amistre64
    • one year ago
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    *union of them

  3. zzr0ck3r
    • one year ago
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    You have two things to worry about \(x>0\) because of the domain of \(\ln(x)\) and \(x-1\ne 0\) because of the \(\dfrac{1}{x-1}\) (we cant divide by \(0\)). So we can use all positive numbers except \(1\). Domain is \(\{x\mid x>0\text{ and } x\ne 1\}=(0,1)\cup (1,\infty)\) Make sense?

  4. amistre64
    • one year ago
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    hmm, might be looking at it in a mirror tho ... the union of the bad parts that is

  5. anonymous
    • one year ago
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    Yes, it makes totally sense! Thanks!

  6. zzr0ck3r
    • one year ago
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    np

  7. zzr0ck3r
    • one year ago
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    I think we want the intersection of the two @amistre64

  8. anonymous
    • one year ago
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    np? :)

  9. zzr0ck3r
    • one year ago
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    no problem @Wikis

  10. anonymous
    • one year ago
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    Of course XD Thought it was a math term that I had missed :D

  11. amistre64
    • one year ago
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    intersection of the domains yes ... i was thinking about the exclusions at first. we want to make sure all the bad parts are avoided for each term

  12. amistre64
    • one year ago
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    if x=2,3 are bad for the first part, and x=2,4,5 are bad for the last part; then we would exclude x=2,3,4,5 was in my head

  13. amistre64
    • one year ago
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    time to build a house ... have fun

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