anonymous
  • anonymous
f(x)=ln(x)+e^(1/x-1). What´s the domain for f? Any suggestions on where to start? :)
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
since the function f(x) has two distinct parts, you should start with them and then find the intersection of the two individual domains, like for Ln(x) the domain would be_
amistre64
  • amistre64
*union of them
zzr0ck3r
  • zzr0ck3r
You have two things to worry about \(x>0\) because of the domain of \(\ln(x)\) and \(x-1\ne 0\) because of the \(\dfrac{1}{x-1}\) (we cant divide by \(0\)). So we can use all positive numbers except \(1\). Domain is \(\{x\mid x>0\text{ and } x\ne 1\}=(0,1)\cup (1,\infty)\) Make sense?

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amistre64
  • amistre64
hmm, might be looking at it in a mirror tho ... the union of the bad parts that is
anonymous
  • anonymous
Yes, it makes totally sense! Thanks!
zzr0ck3r
  • zzr0ck3r
np
zzr0ck3r
  • zzr0ck3r
I think we want the intersection of the two @amistre64
anonymous
  • anonymous
np? :)
zzr0ck3r
  • zzr0ck3r
no problem @Wikis
anonymous
  • anonymous
Of course XD Thought it was a math term that I had missed :D
amistre64
  • amistre64
intersection of the domains yes ... i was thinking about the exclusions at first. we want to make sure all the bad parts are avoided for each term
amistre64
  • amistre64
if x=2,3 are bad for the first part, and x=2,4,5 are bad for the last part; then we would exclude x=2,3,4,5 was in my head
amistre64
  • amistre64
time to build a house ... have fun

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