f(x)=ln(x)+e^(1/x-1). What´s the domain for f? Any suggestions on where to start? :)

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f(x)=ln(x)+e^(1/x-1). What´s the domain for f? Any suggestions on where to start? :)

Calculus1
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since the function f(x) has two distinct parts, you should start with them and then find the intersection of the two individual domains, like for Ln(x) the domain would be_
*union of them
You have two things to worry about \(x>0\) because of the domain of \(\ln(x)\) and \(x-1\ne 0\) because of the \(\dfrac{1}{x-1}\) (we cant divide by \(0\)). So we can use all positive numbers except \(1\). Domain is \(\{x\mid x>0\text{ and } x\ne 1\}=(0,1)\cup (1,\infty)\) Make sense?

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hmm, might be looking at it in a mirror tho ... the union of the bad parts that is
Yes, it makes totally sense! Thanks!
np
I think we want the intersection of the two @amistre64
np? :)
no problem @Wikis
Of course XD Thought it was a math term that I had missed :D
intersection of the domains yes ... i was thinking about the exclusions at first. we want to make sure all the bad parts are avoided for each term
if x=2,3 are bad for the first part, and x=2,4,5 are bad for the last part; then we would exclude x=2,3,4,5 was in my head
time to build a house ... have fun

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