tmagloire1
  • tmagloire1
An ice block is melting at the rate of 1.5 inches per hour. How fast is the surface area of the ice cube changing at the instant the ice block has a side length of 2 inches? −12 in2/hour −18 in2/hour −36 in2/hour −24 in2/hour
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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welshfella
  • welshfella
if side lenght = s Area A = 6s^2 ds/dt = 1.5 dA/ds = 12x = 24 at s = 2 Rate of change of surface area at s = 2 = dA/dt is dA/dt = ds/dt *dA/ds
tmagloire1
  • tmagloire1
Okay but how do I find dA/dt @welshfella
welshfella
  • welshfella
check my post i found dA/ds in that

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welshfella
  • welshfella
dA/dt = ds/dt * dA/ds = 1.5 * 24
tmagloire1
  • tmagloire1
Ohhh so it would be 1.5(24)
welshfella
  • welshfella
yea
tmagloire1
  • tmagloire1
But - because it's falling?
welshfella
  • welshfella
oh right my mistake its -36
tmagloire1
  • tmagloire1
Okay I understand thank you for your help!
welshfella
  • welshfella
yw

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