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tmagloire1
 one year ago
An ice block is melting at the rate of 1.5 inches per hour. How fast is the surface area of the ice cube changing at the instant the ice block has a side length of 2 inches?
−12 in2/hour
−18 in2/hour
−36 in2/hour
−24 in2/hour
tmagloire1
 one year ago
An ice block is melting at the rate of 1.5 inches per hour. How fast is the surface area of the ice cube changing at the instant the ice block has a side length of 2 inches? −12 in2/hour −18 in2/hour −36 in2/hour −24 in2/hour

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.2if side lenght = s Area A = 6s^2 ds/dt = 1.5 dA/ds = 12x = 24 at s = 2 Rate of change of surface area at s = 2 = dA/dt is dA/dt = ds/dt *dA/ds

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Okay but how do I find dA/dt @welshfella

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2check my post i found dA/ds in that

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2dA/dt = ds/dt * dA/ds = 1.5 * 24

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh so it would be 1.5(24)

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0But  because it's falling?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2oh right my mistake its 36

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Okay I understand thank you for your help!
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