## anonymous one year ago Starting from rest, a 5.00 kg steel sphere rolls down a frictionless ramp with a height of 4.00 m. What is the sphere's speed when it reaches the bottom of the ramp? (Use 9.80 for the value of "g.") WHAT FORMULA DO I NEED TO USE ??????

its potential energy at top $$mgh$$ should equal its kinetic energy at the bottom $$\frac{1}{2} m v^2 + \frac{1}{2} I \omega^2$$ you will need its radius to do that, and the formula for the moment of inertia of sphere about its centre |dw:1442504082326:dw|