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kiiraa_x3
 one year ago
help in math>
kiiraa_x3
 one year ago
help in math>

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kiiraa_x3
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442506905537:dw

kiiraa_x3
 one year ago
Best ResponseYou've already chosen the best response.0Simplify the expression and rewrite in rational exponent

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y ·\sqrt[4]{4^3}}{ 3x^\frac{ 1 }{ 2 } ·4\sqrt[3]{x^2} }\] is this right ?

kiiraa_x3
 one year ago
Best ResponseYou've already chosen the best response.0In the sq root its y^3 not 4^3 other then that its right :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0oh okay thanks\[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y ·\sqrt[4]{y^3}}{ 3x^\frac{ 1 }{ 2 } ·4\sqrt[3]{x^2} }\] we should apply exponent rules first you should convert radical to exponent form \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes denominator of the fraction

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm \sqrt[4]{y^3}= y^\frac{ ?? }{ ?? }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0the power of the variable is 3 thats what you should write in the numerator

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right oh okay thanks\[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y · {y^\frac{3}{4}}}{ 3x^\frac{ 1 }{ 2 } ·4\sqrt[3]{x^2} }\] what about \[\sqrt[3]{x^2}=??\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y · {y^\frac{3}{4}}}{ 3x^\frac{ 1 }{ 2 } ·4· x^\frac{2}{3} }\] when we multiply same bases we should `ADD` their exponents \[\huge\rm x^m · x^n=x^{m+n}\] apply this exponent rule

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0y is same as y to the one power \[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y^1 · {y^\frac{3}{4}}}{ 3x^\frac{ 1 }{ 2 } ·4· x^\frac{2}{3} }\] now add the exponent of the same base at the numerator let me know what you get

kiiraa_x3
 one year ago
Best ResponseYou've already chosen the best response.05/3 for x and 3/4 for y ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0how did you get 5/3 for x first deal with the numerator add the exponent of the same and there is y \[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·\color{reD}{24y^1 · {y^\frac{3}{4}}}}{ 3x^\frac{ 1 }{ 2 } ·4· x^\frac{2}{3} }\] add the exponent

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm 24y^1 · 1y^\frac{ 3 }{ 4} \] bases are same (y) so add exponents and multiply the coefficient (24· 1)y^{1+3/4}
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