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kiiraa_x3

  • one year ago

help in math>

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  1. kiiraa_x3
    • one year ago
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    |dw:1442506905537:dw|

  2. kiiraa_x3
    • one year ago
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    Simplify the expression and rewrite in rational exponent

  3. kiiraa_x3
    • one year ago
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    @Nnesha @nincompoop

  4. Nnesha
    • one year ago
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    \[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y ·\sqrt[4]{4^3}}{ 3x^\frac{ 1 }{ 2 } ·4\sqrt[3]{x^2} }\] is this right ?

  5. kiiraa_x3
    • one year ago
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    In the sq root its y^3 not 4^3 other then that its right :)

  6. Nnesha
    • one year ago
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    oh okay thanks\[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y ·\sqrt[4]{y^3}}{ 3x^\frac{ 1 }{ 2 } ·4\sqrt[3]{x^2} }\] we should apply exponent rules first you should convert radical to exponent form \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes denominator of the fraction

  7. Nnesha
    • one year ago
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    \[\huge\rm \sqrt[4]{y^3}= y^\frac{ ?? }{ ?? }\]

  8. kiiraa_x3
    • one year ago
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    y 8/4

  9. Nnesha
    • one year ago
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    hmm 8 ?

  10. Nnesha
    • one year ago
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    the power of the variable is 3 thats what you should write in the numerator

  11. kiiraa_x3
    • one year ago
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    Oops 3/4

  12. Nnesha
    • one year ago
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    yes right oh okay thanks\[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y · {y^\frac{3}{4}}}{ 3x^\frac{ 1 }{ 2 } ·4\sqrt[3]{x^2} }\] what about \[\sqrt[3]{x^2}=??\]

  13. kiiraa_x3
    • one year ago
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    X 2/3

  14. Nnesha
    • one year ago
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    \[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y · {y^\frac{3}{4}}}{ 3x^\frac{ 1 }{ 2 } ·4· x^\frac{2}{3} }\] when we multiply same bases we should `ADD` their exponents \[\huge\rm x^m · x^n=x^{m+n}\] apply this exponent rule

  15. kiiraa_x3
    • one year ago
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    Okay

  16. Nnesha
    • one year ago
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    y is same as y to the one power \[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·24y^1 · {y^\frac{3}{4}}}{ 3x^\frac{ 1 }{ 2 } ·4· x^\frac{2}{3} }\] now add the exponent of the same base at the numerator let me know what you get

  17. kiiraa_x3
    • one year ago
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    5/3 for x and 3/4 for y ?

  18. Nnesha
    • one year ago
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    how did you get 5/3 for x first deal with the numerator add the exponent of the same and there is y \[\large\rm \frac{ x^\frac{ 3 }{ 2 } ·\color{reD}{24y^1 · {y^\frac{3}{4}}}}{ 3x^\frac{ 1 }{ 2 } ·4· x^\frac{2}{3} }\] add the exponent

  19. Nnesha
    • one year ago
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    \[\huge\rm 24y^1 · 1y^\frac{ 3 }{ 4} \] bases are same (y) so add exponents and multiply the coefficient (24· 1)y^{1+3/4}

  20. kiiraa_x3
    • one year ago
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    9/2?

  21. Nnesha
    • one year ago
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    how did you get 9/2 ?

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