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YumYum247
 one year ago
Someone help me please!!!!!! :")
YumYum247
 one year ago
Someone help me please!!!!!! :")

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0I need help with question 25, a,b,c

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0What does it mean by "coupling"?!?!??!?!?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0do you want me to upload my work?????? i've tried to do the question but idk if it's even right tho :(

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0@nincompoop @TheSmartOne

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella Please help me!!!! :")

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@peachpi Can you please help me?!!?!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Thank you peachpi, my throat is all dried up from writing out loud to people for help...:"(

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0and Welsshfella!! :")

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1my physics is pretty rusty i'm afraid..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0seriously, I have no confidence in this. It's a wild shot in the dark. I'm thinking for a) you need to account for the mass of all 15 cars and for b) only the last 8dw:1442519089103:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0that's what i did....but i'm not too sure either.....and Welfella....Thank you for even attempting to help me. :")

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1you use Newton's second law of course F = ma and the third law? which deals with equal and opposite reactions

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0So this is what i did, first i multiplied the total mass of the 15cars = 96000Kg by the acceleration to get the net force of the train pushing on the buggies. (19,200N)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1the coupling is the connection between the engine and the first car and also between all the 15 cars. It will be a rigid bar which will be in tension.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442519725559:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0To find the force on the "coupling" between car number 8 and 9. first i counted how many cars number 8 is from 15 which is 8...i think...i multiplied the mass of all 8 cars by the acceleration and then counted the mass of all the cars from 9 to 15 and multiplied their mass by ht acceleration and subtracted the net force from 8 to 9 to get the net force between cars 8 and 9.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1the above is a simple case with one engine and one car

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0yes @welshfella did you see the resolution of the questions i uploaded?!?!?!?!?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1the tension in the coupling can be found by Newtons 2nd law T = m * a = 6400 * 0.2 = 1280 N

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1No i'll take a look

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0true but have you seen how i attempted to do the next question.....

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1I'm afraid I cant see it very well with my old eyes!!! lol

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Aaawwnnn, try to zoom in...:)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1you are on the right track, I believe

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Ok can you please help me find how far along the track the train must have travelled in 2 minutes after starting??????/

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0the acceleration of the train is 0.20m/sec^2 and the total mass of the train is 96000Kg, and the net force on the buggies with all the load is 19,200N.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use the kinematic formula since acceleration is constant \[d=v_0t+\frac{ 1 }{ 2 }at^2\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but what is the initial velocity of the train tho :"(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00, the train is initially at rest

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0oh....the train is motionless....so Vi = om/sec.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok just last question.....did i do questu=ion "B" right????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0just take a look at the work i've uploaded....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Ok thank you and i LOVE you!!!! :")

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol let me know how this turns out.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442524560809:dw
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