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anonymous

  • one year ago

WILL MEDAL Solve x3 = 64/27.

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  1. anonymous
    • one year ago
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    64/81=x

  2. anonymous
    • one year ago
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    @firedupme did u get it

  3. anonymous
    • one year ago
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    ??!

  4. anonymous
    • one year ago
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    hold on

  5. MrNood
    • one year ago
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    \[x ^{3} =\frac{ 64 }{ 27 }\] so take cube root to find x \[\sqrt[3]{x ^{3}} = x = \sqrt[3]{\frac{ 64 }{ 27}} = \frac{ \sqrt[3]{64} }{\sqrt[3]{27} }\]

  6. anonymous
    • one year ago
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    @MrNood is correct. He got it to it before me :P good job.

  7. MrNood
    • one year ago
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    @moha_10 you have misread the question - it is x^3 - NOT 3x

  8. anonymous
    • one year ago
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    im pretty sure my answer is wrong

  9. anonymous
    • one year ago
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    im terrible at these questions

  10. anonymous
    • one year ago
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    alright is my mistake sorry @MrNood

  11. anonymous
    • one year ago
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    the answers are ±8 / 3 8 / 3 ±4 / 3 4 / 3

  12. anonymous
    • one year ago
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    @MrNood im really bad at these so just bare with me.

  13. MrNood
    • one year ago
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    I wrote all but the last step above the answer is \[x= \sqrt[3]{64}\div \sqrt[3]{27}\] it turns out that those 2 numbers are VERY easy to get the cube root use your calculator - or just use some common sense what number is cubed to make 64? what number is cubed to make 27?

  14. anonymous
    • one year ago
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    8

  15. anonymous
    • one year ago
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    8/3

  16. anonymous
    • one year ago
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    what about the ±?

  17. MrNood
    • one year ago
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    8 cubed = 8x8x8 = 492

  18. anonymous
    • one year ago
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    so the answer is 8/3

  19. anonymous
    • one year ago
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    @MrNood

  20. anonymous
    • one year ago
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    PLZ

  21. MrNood
    • one year ago
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    I just showed you that 8 cubed is NOT 64 so therefore cuberoot of 64 is not 8 so 8 is not in the answer

  22. anonymous
    • one year ago
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    so it would have to be 4/3. i just don't get the ±

  23. anonymous
    • one year ago
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    so is it ±4/3 or just 4/3 ?

  24. MrNood
    • one year ago
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    as an example \[\sqrt{4} =\pm 2\] BECAUSE -2 x -2 = 4 AND 2 X 2 = 4 is this true for CUBE root?

  25. anonymous
    • one year ago
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    yes

  26. anonymous
    • one year ago
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    so ±4/3

  27. anonymous
    • one year ago
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    right?

  28. anonymous
    • one year ago
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    Nope that waws wrong ,,,, fun

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