anonymous
  • anonymous
WILL MEDAL Solve x3 = 64/27.
Mathematics
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anonymous
  • anonymous
WILL MEDAL Solve x3 = 64/27.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
64/81=x
anonymous
  • anonymous
@firedupme did u get it
anonymous
  • anonymous
??!

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anonymous
  • anonymous
hold on
MrNood
  • MrNood
\[x ^{3} =\frac{ 64 }{ 27 }\] so take cube root to find x \[\sqrt[3]{x ^{3}} = x = \sqrt[3]{\frac{ 64 }{ 27}} = \frac{ \sqrt[3]{64} }{\sqrt[3]{27} }\]
anonymous
  • anonymous
@MrNood is correct. He got it to it before me :P good job.
MrNood
  • MrNood
@moha_10 you have misread the question - it is x^3 - NOT 3x
anonymous
  • anonymous
im pretty sure my answer is wrong
anonymous
  • anonymous
im terrible at these questions
anonymous
  • anonymous
alright is my mistake sorry @MrNood
anonymous
  • anonymous
the answers are ±8 / 3 8 / 3 ±4 / 3 4 / 3
anonymous
  • anonymous
@MrNood im really bad at these so just bare with me.
MrNood
  • MrNood
I wrote all but the last step above the answer is \[x= \sqrt[3]{64}\div \sqrt[3]{27}\] it turns out that those 2 numbers are VERY easy to get the cube root use your calculator - or just use some common sense what number is cubed to make 64? what number is cubed to make 27?
anonymous
  • anonymous
8
anonymous
  • anonymous
8/3
anonymous
  • anonymous
what about the ±?
MrNood
  • MrNood
8 cubed = 8x8x8 = 492
anonymous
  • anonymous
so the answer is 8/3
anonymous
  • anonymous
anonymous
  • anonymous
PLZ
MrNood
  • MrNood
I just showed you that 8 cubed is NOT 64 so therefore cuberoot of 64 is not 8 so 8 is not in the answer
anonymous
  • anonymous
so it would have to be 4/3. i just don't get the ±
anonymous
  • anonymous
so is it ±4/3 or just 4/3 ?
MrNood
  • MrNood
as an example \[\sqrt{4} =\pm 2\] BECAUSE -2 x -2 = 4 AND 2 X 2 = 4 is this true for CUBE root?
anonymous
  • anonymous
yes
anonymous
  • anonymous
so ±4/3
anonymous
  • anonymous
right?
anonymous
  • anonymous
Nope that waws wrong ,,,, fun

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