anonymous one year ago WILL MEDAL Solve x3 = 64/27.

1. anonymous

64/81=x

2. anonymous

@firedupme did u get it

3. anonymous

??!

4. anonymous

hold on

5. MrNood

$x ^{3} =\frac{ 64 }{ 27 }$ so take cube root to find x $\sqrt[3]{x ^{3}} = x = \sqrt[3]{\frac{ 64 }{ 27}} = \frac{ \sqrt[3]{64} }{\sqrt[3]{27} }$

6. anonymous

@MrNood is correct. He got it to it before me :P good job.

7. MrNood

@moha_10 you have misread the question - it is x^3 - NOT 3x

8. anonymous

im pretty sure my answer is wrong

9. anonymous

im terrible at these questions

10. anonymous

alright is my mistake sorry @MrNood

11. anonymous

the answers are ±8 / 3 8 / 3 ±4 / 3 4 / 3

12. anonymous

@MrNood im really bad at these so just bare with me.

13. MrNood

I wrote all but the last step above the answer is $x= \sqrt[3]{64}\div \sqrt[3]{27}$ it turns out that those 2 numbers are VERY easy to get the cube root use your calculator - or just use some common sense what number is cubed to make 64? what number is cubed to make 27?

14. anonymous

8

15. anonymous

8/3

16. anonymous

17. MrNood

8 cubed = 8x8x8 = 492

18. anonymous

19. anonymous

@MrNood

20. anonymous

PLZ

21. MrNood

I just showed you that 8 cubed is NOT 64 so therefore cuberoot of 64 is not 8 so 8 is not in the answer

22. anonymous

so it would have to be 4/3. i just don't get the ±

23. anonymous

so is it ±4/3 or just 4/3 ?

24. MrNood

as an example $\sqrt{4} =\pm 2$ BECAUSE -2 x -2 = 4 AND 2 X 2 = 4 is this true for CUBE root?

25. anonymous

yes

26. anonymous

so ±4/3

27. anonymous

right?

28. anonymous

Nope that waws wrong ,,,, fun